Elementary Principles Of Chemical Processes
Elementary Principles Of Chemical Processes
4th Edition
ISBN: 9781119254003
Author: Richard M. Felder And Ronald W. Rousseau
Publisher: WILEY
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Chapter 2, Problem 2.13P
Interpretation Introduction

(a)

Interpretation:

How many panels are required.

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

Interpretation Introduction

(b)

Interpretation:  What would be total cost saving

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

Interpretation Introduction

(c)

Interpretation:  Motivation to decide to install the solar panels

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home

and other small business are measured in kilowatt hour while the consumption by medium and

large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

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Q. VI: An equimolar liquid mixture of benzene and toluene is separated into two product streams by distillation. At each point in the column some of the liquid vaporizes and some of the vapor stream condenses. The vapor leaving the top of the column, which contains 97 mole% benzene, is completely condensed and split into two equal fractions: one is taken off as the overhead product stream, and the other (the reflux) is recycled to the top of the column. The overhead product stream contains 89.2% of the benzene fed to the column. The liquid leaving the bottom of the column is fed to a partial reboiler in which 45% of it is vaporized. The vapor generated in the reboiler (the boilup) is recycled to become the rising vapor stream in the column, and the residual reboiler liquid is taken off as the bottom product stream. The compositions of the streams leaving the reboiler are governed by the relation, YB/(1 - YB) XB/(1 - XB) = 2.25 where YB and XB are the mole fractions of benzene in the…
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