Chapter 2, Problem 2.13P

Interpretation Introduction

(a)

Interpretation:

How many panels are required.

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

$\begin{array}{c}\text{1}\text{kWh}=\text{1000}\times \text{60}\times \text{60}\\ =\text{3600000}\text{J}\end{array}$

Interpretation Introduction

(b)

Interpretation:  What would be total cost saving

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

$\begin{array}{c}\text{1}\text{kWh}=\text{1000}\times \text{60}\times \text{60}\\ =\text{3600000}\text{J}\end{array}$

Interpretation Introduction

(c)

Interpretation:  Motivation to decide to install the solar panels

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home

and other small business are measured in kilowatt hour while the consumption by medium and

large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

$\begin{array}{c}\text{1}\text{kWh}=\text{1000}\times \text{60}\times \text{60}\\ =\text{3600000}\text{J}\end{array}$