PRIN.OF GEOTECHNICAL...-MINDTAP(2 SEM)
9th Edition
ISBN: 9781305971271
Author: Das
Publisher: CENGAGE L
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Chapter 2, Problem 2.11P
The grain-size characteristics of a soil are given in the following table.
a. Draw the grain-size distribution curve.
b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system.
c. Repeat Part b using the USDA system.
d. Repeat Part b using the AASHTO system.
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Example 5.2: Design Example of a Square Foundation for a Colum
Figure A.3a shows a square column foundation with the followin
conditions:
Live load=L=675 kN
Dead load D= 1125 kN
Allowable gross soil-bearing capacity 145 kN/m²
Column size-0.5 m x 0.5 m
-20.68 MN/m²
1,413.7 MN/m²
Let it be required to design the column foundation.
1.25m-D
L-675 AN
D-1125 AN
(a)
Column section-
05 m x 0.5m
Example 5.3: Design Example of a Rectangular Foundation for
Column
This section describes the design of a rectangular foundation to support a column having
dimensions of 0.4 m x 0.4 m in cross section. Other details are as follows:
Dead load D= 290 kN
Live load L= 110 kN
Depth from the ground surface to the top of the foundation = 1.2 m
Allowable gross soil-bearing capacity = 120 kN/m²
Maximum width of foundation = B = 1.5 m
f, = 413.7 MN/m²
f=20.68 MN/m²
Unit weight of soil = y = 17.27 kN/m³
Unit weight of concrete = y₁ = 22.97 kN/m³
General Considerations
For this design, let us assume a foundation thickness of 0.45 m (Figure A.4a). The weight
of foundation/m² = 0.45 y = (0.45) (22.97) = 10.34 kN/m², and the weight of soil above
the foundation/m² = (1.2)y = (1.2) (17.27) = 20.72 kN/m² Hence, the net allowable soil-
bearing capacity Iqata] =120-10.34-20.72 = 88.94 kN/m²
The required area of the foundation = (D+L)/4(all) = (290 + 110)/88.94 =
4.5 m². Hence, the length of the foundation…
Chapter 2 Solutions
PRIN.OF GEOTECHNICAL...-MINDTAP(2 SEM)
Ch. 2 - For a gravel with D60 = 0.48 mm, D30 = 0.25 mm,...Ch. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - The following are the results of a sieve analysis....Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - The following are the results of a sieve and...Ch. 2 - Repeat Problem 2.8 using the following data. 2.8...Ch. 2 - Repeat Problem 2.8 using the following data. 2.8...
Ch. 2 - The grain-size characteristics of a soil are given...Ch. 2 - Repeat Problem 2.11 with the following data. 2.11...Ch. 2 - Repeat Problem 2.11 with the following data. 2.11...Ch. 2 - A hydrometer test has the following result: Gs =...Ch. 2 - Repeat Problem 2.14 with the following values: Gs...Ch. 2 - Three groups of students from the Geotechnical...Ch. 2 - Refer to Problem 2.C.1. Results of the sieve...
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