one solution of the given system.

Question

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Answer 1

Question

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

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Answer 2

Question

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

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Answer 3

Question

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

Answer 6

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

Answer 7

Chapter 2, Problem 1RE

To determine

To find:one solution of the given system.

Answer 8

Expert Solution & Answer

Answer to Problem 1RE

The one of the solutions of the system is $x=0,y=0$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information:

The system of equations are $dxdt=|x|siny$ and $dydt=|y|cosx$ .

Formulas used:

Atequilibrium, all the rates are equal to zero. The equilibrium point is alsosolution of the system.

Calculation:

Solve for equilibrium points.

That is solve for $dxdt=0$ and $dydt=0$

$dxdy=0⇒|x|siny=0⇒|x|=0 or siny=0⇒x=0 or y=0......(1)$

Similarly,

$dydx=0⇒|y|cosx=0⇒|y|=0 or cosx=0⇒y=0 or x=(π/2)+2πn,(3π/2)+2πn$

Hence, one solution of the system is $x=0,y=0$ .

Answer 12

Ch. 2.1 - Exercises 1-6 refer to the following systems of...Ch. 2.1 - Exercises 1-6 refer to the following systems of...Ch. 2.1 - Exercises 1-6 refer to the following systems of...Ch. 2.1 - Exercises 1-6 refer to the following systems of...Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Consider the predator-prey system...Ch. 2.1 - Consider the predator-prey system dRdt=2R(1R...Ch. 2.1 - Exercises 9-14 refer to the predator-prey and the...Ch. 2.1 - Exercises 9-14 refer to the predator-prey and the...

one solution of the given system.

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To find:one solution of the given system.

Answer to Problem 1RE

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