The Analysis of Biological Data
2nd Edition
ISBN: 9781936221486
Author: Michael C. Whitlock, Dolph Schluter
Publisher: W. H. Freeman
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Chapter 2, Problem 1PP
(a)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(a)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:.The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation:As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another. Therefore the area of the shaded part is about one-fourth of the total area of the graph. Therefore the relative frequency of the shaded area is
(b)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(b)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:.The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation: As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another and height of last two bars is exactly half of first two bars. Which makes the total area of last two bars equal to one complete bar. Therefore the area of the shaded part is about one-third of the total area of the graph. Therefore the relative frequency of the shaded area is
(c)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(c)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:. The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation: As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another. Therefore the area of the shaded part is about one-third of the total area of the graph. Therefore the relative frequency of the shaded area is
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2.2, 13.2-13.3)
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The accompanying table contains the data for the amounts (in oz) in cans of a certain soda. The cans are labeled to indicate that the contents are 20 oz of soda. Use the sign test and
0.05 significance level to test the claim that cans of this soda are filled so that the median amount is 20 oz. If the median is not 20 oz, are consumers being cheated?
Click the icon to view the data.
What are the null and alternative hypotheses?
OA. Ho: Medi
More Info
H₁: Medi
OC. Ho: Medi
H₁: Medi
Volume (in ounces)
20.3
20.1
20.4
Find the test stat
20.1
20.5
20.1
20.1
19.9
20.1
Test statistic =
20.2
20.3
20.3
20.1
20.4
20.5
Find the P-value
19.7
20.2
20.4
20.1
20.2
20.2
P-value=
(R
19.9
20.1
20.5
20.4
20.1
20.4
Determine the p
20.1
20.3
20.4
20.2
20.3
20.4
Since the P-valu
19.9
20.2
19.9
Print
Done
20 oz
20 oz
20 oz
20 oz
ce that the consumers are being cheated.
T
Teenage obesity (O), and weekly fast-food meals (F), among some selected Mississippi teenagers are:
Name Obesity (lbs) # of Fast-foods per week
Josh
185
10
Karl
172
8
Terry
168
9
Kamie
Andy
204
154
12
6
(a) Compute the variance of Obesity, s²o, and the variance of fast-food meals, s², of this data. [Must show full work].
(b) Compute the Correlation Coefficient between O and F. [Must show full work].
(c) Find the Coefficient of Determination between O and F. [Must show full work].
(d) Obtain the Regression equation of this data. [Must show full work].
(e) Interpret your answers in (b), (c), and (d). (Full explanations required).
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?
Chapter 2 Solutions
The Analysis of Biological Data
Ch. 2 - Prob. 1PPCh. 2 - Prob. 2PPCh. 2 - Prob. 3PPCh. 2 - Prob. 4PPCh. 2 - Prob. 5PPCh. 2 - Prob. 6PPCh. 2 - Prob. 7PPCh. 2 - Prob. 8PPCh. 2 - Prob. 9PPCh. 2 - Prob. 10PP
Ch. 2 - Prob. 11PPCh. 2 - Prob. 12PPCh. 2 - Prob. 13PPCh. 2 - Prob. 14PPCh. 2 - Prob. 15PPCh. 2 - Prob. 16PPCh. 2 - Prob. 17PPCh. 2 - Prob. 18PPCh. 2 - Prob. 19APCh. 2 - Prob. 20APCh. 2 - Prob. 21APCh. 2 - Prob. 22APCh. 2 - Prob. 23APCh. 2 - Prob. 24APCh. 2 - Prob. 25APCh. 2 - Prob. 26APCh. 2 - Prob. 27APCh. 2 - Prob. 28APCh. 2 - Prob. 29APCh. 2 - Prob. 30APCh. 2 - Prob. 31APCh. 2 - Prob. 32APCh. 2 - Prob. 33APCh. 2 - Prob. 34APCh. 2 - Prob. 35APCh. 2 - Prob. 36APCh. 2 - Prob. 37AP
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