The Analysis of Biological Data
2nd Edition
ISBN: 9781936221486
Author: Michael C. Whitlock, Dolph Schluter
Publisher: W. H. Freeman
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Chapter 2, Problem 1PP
(a)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(a)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:.The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation:As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another. Therefore the area of the shaded part is about one-fourth of the total area of the graph. Therefore the relative frequency of the shaded area is
(b)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(b)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:.The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation: As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another and height of last two bars is exactly half of first two bars. Which makes the total area of last two bars equal to one complete bar. Therefore the area of the shaded part is about one-third of the total area of the graph. Therefore the relative frequency of the shaded area is
(c)
To determine
To find: To estimate the relative frequency of the shaded area by eye.
(c)
Expert Solution
Answer to Problem 1PP
The relative frequency of the shaded area is
Explanation of Solution
Given:
Calculation:. The area of the rectangular bar of a histogram is proportional to the relative frequency of the considering numerical variable.
Interpretation: As the area of the rectangular bar of the histogram proportional to the relative frequency, the area of the shaded bar should be estimated by eye, comparing to the total area of the graph. The width of each bar of the histogram is equal to one another. Therefore the area of the shaded part is about one-third of the total area of the graph. Therefore the relative frequency of the shaded area is
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Bob and Teresa each collect their own samples to test the same hypothesis. Bob’s p-value turns out to be 0.05, and Teresa’s turns out to be 0.01.
Why don’t Bob and Teresa get the same p-values?
Who has stronger evidence against the null hypothesis: Bob or Teresa?
Review a classmate's Main Post.
1. State if you agree or disagree with the choices made for additional analysis
that can be done beyond the frequency table.
2. Choose a measure of central tendency (mean, median, mode) that you
would like to compute with the data beyond the frequency table. Complete
either a or b below.
a. Explain how that analysis can help you understand the data better.
b. If you are currently unable to do that analysis, what do you think you
could do to make it possible? If you do not think you can do
anything, explain why it is not possible.
Chapter 2 Solutions
The Analysis of Biological Data
Ch. 2 - Prob. 1PPCh. 2 - Prob. 2PPCh. 2 - Prob. 3PPCh. 2 - Prob. 4PPCh. 2 - Prob. 5PPCh. 2 - Prob. 6PPCh. 2 - Prob. 7PPCh. 2 - Prob. 8PPCh. 2 - Prob. 9PPCh. 2 - Prob. 10PP
Ch. 2 - Prob. 11PPCh. 2 - Prob. 12PPCh. 2 - Prob. 13PPCh. 2 - Prob. 14PPCh. 2 - Prob. 15PPCh. 2 - Prob. 16PPCh. 2 - Prob. 17PPCh. 2 - Prob. 18PPCh. 2 - Prob. 19APCh. 2 - Prob. 20APCh. 2 - Prob. 21APCh. 2 - Prob. 22APCh. 2 - Prob. 23APCh. 2 - Prob. 24APCh. 2 - Prob. 25APCh. 2 - Prob. 26APCh. 2 - Prob. 27APCh. 2 - Prob. 28APCh. 2 - Prob. 29APCh. 2 - Prob. 30APCh. 2 - Prob. 31APCh. 2 - Prob. 32APCh. 2 - Prob. 33APCh. 2 - Prob. 34APCh. 2 - Prob. 35APCh. 2 - Prob. 36APCh. 2 - Prob. 37AP
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