To modify the description for VR39 to “Virus detection and removal” in the ScheduledClients table.

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Chapter 2, Problem 15BCEQBE

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To modify the description for VR39 to “Virus detection and removal” in the ScheduledClients table.

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- | العنوان I need a detailed drawing with explanation so A 4 شكا +x-pu +965 Taylor Series Approximation Example- H.W More terms used implies better approximation f(x)+ f(x) Zero order First order 1.0 0.5 x-0 Second order True f(x) f(x) • flx;+ 1) = f(x) + fƒ '\x;}h √(x,+ 1) = f(x) + f (x)h + "(x) 2 f(x1) X+1-1 f(x) 0.1x 0.15x³-0.5x²-0.25x+1.2 Taylor Series Approximation H.w: Smaller step size implies smaller error Errors 100+ F(x) Zero order First order Second order 0.5 Reduced step size 0 x, 0 f(x+1)f(x,) + ƒ\x,}h 51 f(x + 1) − f(x) + (x)+2 ((x1) +1-1 Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5 iterations (or & s= 5%) for f(x) 0.1x 0.15x³-0.5x2- 0.25x+1.2 マ 52

Home Work Use Taylor's series expansion to Compute the true and approximate percent relative errors & and εa for x = π/6, use 6 iterations for the series. sin(x) == x-

Taylor Series Approximation Example- H.W More terms used implies better approximation f(x) 4 f(x) Zero order f(x + 1) = f(x;) First order f(x; + 1) = f(x;) + f'(x;)h 1.0 Second order 0.5 True f(x + 1) = f(x) + f'(x)h + ƒ"(x;) h2 2! f(x+1) 0 x; = 0 x+1 = 1 x h f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2 51 Taylor Series Approximation H.w: Smaller step size implies smaller error Errors f(x) + f(x,) Zero order f(x,+ 1) = f(x) First order 1.0 0.5 Reduced step size Second order True f(x + 1) = f(x) + f'(x)h f(x; + 1) = f(x) + f'(x)h + "(xi) h2 f(x,+1) O x₁ = 0 x+1=1 Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5 iterations (or & s= 5%) for f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2 52