The atomic number and the ground state configuration of the next alkali metal after Francium is to be predicted. Concept Introduction: The elements that belong to the group IA (1) of the periodic table are known as alkali methods. They are very reactive and electro positive in nature. The atomic number of an element in this group can be obtained by the addition of the magic number to its previous element. The addition from top to bottom is done in the according to the series 2 , 8 , 8 , 18 , 18 , 32 , 32 . To determine: The atomic number of the alkali metal that would come after Francium and its ground-state electronic configuration.
The atomic number and the ground state configuration of the next alkali metal after Francium is to be predicted. Concept Introduction: The elements that belong to the group IA (1) of the periodic table are known as alkali methods. They are very reactive and electro positive in nature. The atomic number of an element in this group can be obtained by the addition of the magic number to its previous element. The addition from top to bottom is done in the according to the series 2 , 8 , 8 , 18 , 18 , 32 , 32 . To determine: The atomic number of the alkali metal that would come after Francium and its ground-state electronic configuration.
Solution Summary: The author explains that the atomic number and ground state configuration of the next alkali metal after Francium is to be predicted.
Definition Definition Number of protons in the nucleus of an atom. It uniquely identifies an element, as the number of protons determines the element's properties. The periodic table of elements is arranged based on increasing atomic numbers, allowing scientists to easily locate and study elements.
Chapter 2, Problem 132E
Interpretation Introduction
Interpretation:
The atomic number and the ground state configuration of the next alkali metal after Francium is to be predicted.
Concept Introduction:
The elements that belong to the group IA (1) of the periodic table are known as alkali methods. They are very reactive and electro positive in nature. The atomic number of an element in this group can be obtained by the addition of the magic number to its previous element. The addition from top to bottom is done in the according to the series
2,8,8,18,18,32,32.
To determine: The atomic number of the alkali metal that would come after Francium and its ground-state electronic configuration.
5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the
product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15%
glycerin by weight.
If the original charge is 500 kg, evaluate;
e. The ratio of sucrose to water in the original charge (wt/wt).
f. Moles of CO2 evolved.
g. Maximum possible amount of ethanol that could be formed.
h. Conversion efficiency.
i. Per cent excess of excess reactant.
Reactions:
Inversion reaction: C12H22O11 + H2O →2C6H12O6
Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2
Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. cleavage
Bond A
•CH3 + 26.← Cleavage
2°C. +
Bond C
+3°C•
CH3 2C
Cleavage
E
2°C. 26.
weakest bond
Intact molecule
Strongest 3°C 20.
Gund
Largest
argest
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
C
Weakest
bond
A
Produces
Most
Bond
Strongest
Bond
Strongest Gund
produces least stable
radicals
Weakest
Stable radical
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
13°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
• CH3
methyl radical
Formed in Gund A Cleavage
c.…
Chapter 2 Solutions
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