MyLab Programming with Pearson eText -- Access Card -- for Introduction to Java Programming and Data Structures, Comprehensive Version
11th Edition
ISBN: 9780134672816
Author: Liang
Publisher: PEARSON
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Expert Solution & Answer
Chapter 19.8, Problem 19.8.1CP
Explanation of Solution
Erasure:
The erasure is the type which is used to convert the generic type to a raw type. Generics are mostly implemented using erasure approach.
Reason for why Java generics implemented using erasure:
- The generic type information can be compiled and the compiler checks whether the given generic type is safe or not...
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Chapter 19 Solutions
MyLab Programming with Pearson eText -- Access Card -- for Introduction to Java Programming and Data Structures, Comprehensive Version
Ch. 19.2 - Are there any compile errors in (a) and (b)?Ch. 19.2 - Prob. 19.2.2CPCh. 19.2 - Prob. 19.2.3CPCh. 19.3 - Prob. 19.3.1CPCh. 19.3 - Prob. 19.3.2CPCh. 19.3 - Prob. 19.3.3CPCh. 19.3 - Prob. 19.3.4CPCh. 19.4 - Prob. 19.4.1CPCh. 19.4 - Prob. 19.4.2CPCh. 19.5 - Prob. 19.5.1CP
Ch. 19.5 - Prob. 19.5.2CPCh. 19.6 - What is a raw type? Why is a raw type unsafe? Why...Ch. 19.6 - Prob. 19.6.2CPCh. 19.7 - Prob. 19.7.1CPCh. 19.7 - Prob. 19.7.2CPCh. 19.7 - Prob. 19.7.3CPCh. 19.7 - Prob. 19.7.4CPCh. 19.8 - Prob. 19.8.1CPCh. 19.8 - Prob. 19.8.2CPCh. 19.8 - Prob. 19.8.3CPCh. 19.8 - Prob. 19.8.4CPCh. 19.8 - Prob. 19.8.5CPCh. 19.9 - Prob. 19.9.1CPCh. 19.9 - How are the add, multiple, and zero methods...Ch. 19.9 - How are the add, multiple, and zero methods...Ch. 19.9 - What would be wrong if the printResult method is...Ch. 19 - (Revising Listing 19.1) Revise the GenericStack...Ch. 19 - Prob. 19.2PECh. 19 - (Distinct elements in ArrayList) Write the...Ch. 19 - Prob. 19.4PECh. 19 - (Maximum element in an array) Implement the...Ch. 19 - (Maximum element in a two-dimensional array) Write...Ch. 19 - Prob. 19.7PECh. 19 - (Shuffle ArrayList) Write the following method...Ch. 19 - (Sort ArrayList) Write the following method that...Ch. 19 - (Largest element in an ArrayList) Write the...Ch. 19 - Prob. 19.11PE
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