The given decomposition reaction has to be discussed. Concept introduction: Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

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Answer 1

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Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

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Consider the following reaction: 1. 2 N,O5 (g) → 4 NO, (g) + O, (g) The initial concentration of N2O5 was 0.48 mol/L, and 25 minutes after initiating the reaction, all of the N,Os has been consumed. (a) Calculate the average rate of the reaction over this 25-minute time interval. (b) Is it correct to assume that the rate law is Rate = k[N,O5]² based on the balanced chemical equation? Briefly explain your answer.

Assume that the formation of nitrogen dioxide: 2NO(g) + O2(g) 2NO2(g) is an elementary reaction. (a) Write the rate law for this reaction. (b) A sample of air at a certain temperature is contaminated with 2.0 ppm of NO by volume. Under these conditions, can the rate law be simplified? If so, write the simplified rate law. (c) Under the conditions described in part (b), the half-life of the reaction has been estimated to be 6.4 × 103 min. What would the half-life be if the initial concentration of NO were 10 ppm?

Assume that the formation of nitrogen dioxide, 2 NO(g) + 02(g) – 2 NO2(g) is an elementary reaction. (a) Write the rate law for this reaction. (Rate expressions take the general form: rate = k. [A]ª . [B]b.) chemPad О Help Greek - rate=k•[NO]2.[02] rate=k*[NO]^2*[O_2] Correct. (b) A sample of air at a certain temperature is contaminated with 1.9 ppm of NO by volume. Under these conditions, can the rate law be simplified? If so, write the simplified rate law. If not, repeat your answer from above. (Rate expressions take the general form: rate = k . [A]ª . [B]b. Use k' for the new rate constant as needed.) chemPad O Help Greek - rate=k':[NO]2 rate=k*[NO]^2 Correct. (c) Under the conditions described in (b), the half-life of the reaction has been estimated to be 6.7x103 min. What would the half-life be if the initial concentration of NO were 12.4 ppm? 4.0 |1030192 X min Supporting Materials Periodic Table Constants and E Supplemental Data

Answer 2

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Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

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Answer 3

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

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Answer 4

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

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Answer 5

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 6

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 7

Chapter 19.7, Problem 19.11WE

(a)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The given decomposition reaction has to be discussed.

Concept introduction:

Add the two equations, cancelling identical terms on opposite sides of the arrow, to obtain the overall reaction. The cancelled terms will be the intermediates if they were first generated and then consumed. Write rate laws for each elementary step; the one that matches the experimental rate law will be the rate-determining step.

Answer 12

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Answer 15

Ch. 19.3 - Prob. 19.1WE Ch. 19.3 - Write the rate expressions for each of the...Ch. 19.3 - Write the balanced equation corresponding to the...Ch. 19.3 - The diagrams represent a system that initially...Ch. 19.3 - Consider the reaction 4NO2(g)+O2(g)2N2O5(g) At a...Ch. 19.3 - Consider the reaction 4PH3(g)P4(g)+6H2(g) At a...Ch. 19.3 - Prob. 2PPB Ch. 19.3 - Prob. 2PPC Ch. 19.3 - Prob. 19.3.1SR Ch. 19.3 - Prob. 19.3.2SR

Solution Summary: The author explains how to write rate laws for elementary reactions by using the stoichiometric coefficient for each species as its exponent in the rate law.

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