Big Java, Binder Ready Version: Early Objects
Big Java, Binder Ready Version: Early Objects
6th Edition
ISBN: 9781119056447
Author: Cay S. Horstmann
Publisher: WILEY
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Chapter 19.4, Problem 19SC

Explanation of Solution

Statement for the given condition:

The statement to finding the number of distinct words which is equal to 3 is as follows:

int r = list.stream ().filter (w -> w.length () == 3).distinct ().count ();

  • Here, “r” is an integer variable
  • The “filter” method is used to pick out the words that the user wants.
  • The “distinct” method is used to get the unique word from the list...

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Chapter 19 Solutions

Big Java, Binder Ready Version: Early Objects

Ch. 19.3 - Prob. 11SCCh. 19.3 - Prob. 12SCCh. 19.3 - Prob. 13SCCh. 19.3 - Prob. 14SCCh. 19.3 - Prob. 15SCCh. 19.4 - Prob. 16SCCh. 19.4 - Prob. 17SCCh. 19.4 - Prob. 18SCCh. 19.4 - Prob. 19SCCh. 19.4 - Prob. 20SCCh. 19.5 - Prob. 21SCCh. 19.5 - Prob. 22SCCh. 19.5 - Prob. 23SCCh. 19.5 - Prob. 24SCCh. 19.5 - Prob. 25SCCh. 19.6 - Prob. 26SCCh. 19.6 - Prob. 27SCCh. 19.6 - Prob. 28SCCh. 19.6 - Prob. 29SCCh. 19.6 - Prob. 30SCCh. 19.7 - Prob. 31SCCh. 19.7 - Prob. 32SCCh. 19.7 - Prob. 33SCCh. 19.7 - Prob. 34SCCh. 19.7 - Prob. 35SCCh. 19.8 - Prob. 36SCCh. 19.8 - Prob. 37SCCh. 19.8 - Prob. 38SCCh. 19.8 - Prob. 39SCCh. 19.9 - Prob. 40SCCh. 19.9 - Prob. 41SCCh. 19.9 - Prob. 42SCCh. 19.9 - Prob. 43SCCh. 19.9 - Prob. 44SCCh. 19.10 - Prob. 45SCCh. 19.10 - Prob. 46SCCh. 19.10 - Prob. 47SCCh. 19.10 - Prob. 48SCCh. 19.10 - Prob. 49SCCh. 19 - Prob. 1RECh. 19 - Prob. 2RECh. 19 - Prob. 3RECh. 19 - Prob. 4RECh. 19 - Prob. 5RECh. 19 - Prob. 6RECh. 19 - Prob. 7RECh. 19 - Prob. 8RECh. 19 - Prob. 9RECh. 19 - Prob. 10RECh. 19 - Prob. 11RECh. 19 - Prob. 12RECh. 19 - Prob. 13RECh. 19 - Prob. 1PECh. 19 - Prob. 2PECh. 19 - Prob. 3PECh. 19 - Prob. 4PECh. 19 - Prob. 5PECh. 19 - Prob. 6PECh. 19 - Prob. 7PECh. 19 - Prob. 8PECh. 19 - Prob. 9PECh. 19 - Prob. 10PECh. 19 - Prob. 11PECh. 19 - Prob. 12PECh. 19 - Prob. 13PECh. 19 - Prob. 14PECh. 19 - Prob. 15PECh. 19 - Prob. 16PECh. 19 - Prob. 17PECh. 19 - Prob. 18PECh. 19 - Prob. 19PECh. 19 - Prob. 20PECh. 19 - Prob. 1PPCh. 19 - Prob. 2PPCh. 19 - Prob. 3PPCh. 19 - Prob. 4PPCh. 19 - Prob. 5PPCh. 19 - Prob. 6PPCh. 19 - Prob. 7PPCh. 19 - Prob. 8PPCh. 19 - Prob. 9PPCh. 19 - Prob. 10PPCh. 19 - Prob. 11PPCh. 19 - Prob. 12PP
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