Explanation Given information: Length of cord l A B = 1.2 m ∠ θ A = 5 ° Length d = 0.6 m As the pendulum moves between points A and B, the length of pendulum is, l = l A B = 1.2 m The natural circular frequency of pendulum during this motion is, ω n 1 = g l A B ω n 1 = 9.81 1.2 ω n 1 = 2.8592 r a d / s Now, period of oscillation, τ 1 = 2 π ω n 1 τ 1 = 2 × 3.14 2.8592 τ 1 = 2.196 s As the falling from A to B is one quarter, then the period of oscillation in this quarter is, τ A B = 1 4 τ τ A B = 1 4 × 2.196 τ A B = 0.549 s Now, the pendulum moves between point B and C, then the length of the pendulum is, l B C = l A B − d l B C = 1.2 − 0.6 l B C = 0.6 m Again, natural circular frequency during this length of motion of pendulum is, ω n 2 = g l B C ω n 2 = 9 To determine (b) The amplitude θ C .

12th Edition

ISBN: 9781259977305

Author: BEER, Ferdinand P. (ferdinand Pierre), Johnston, E. Russell (elwood Russell), Cornwell, Phillip J., SELF, Brian P.

Publisher: Mcgraw-hill Education,

See similar textbooks

Concept explainers

Free Damped Vibrations

Free vibration is a type of vibration in which the external force is removed after giving the initial displacement to a body/system. In other words, in this type of vibration, force is applied at the initial displacement of the system, and after the init…

Question

Chapter 19.1, Problem 19.16P

To determine

(a)

The time required for the bob to return to point A.

To determine

(b)

The amplitude θC.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 19.1, Problem 19.15P

Chapter 19.1, Problem 19.17P

Students have asked these similar questions

Quiz Number 6 - Middle Initial is B, G, L, Q, V 1. A connecting rod supported by a knife-edge at point A. For small oscillations the angular acceleration of the connecting rod is governed by the relation a = -60 where a is expressed in rad/s² and 0 in radians. Knowing that the connecting rod is released from rest when 0 = 22.4°, determine a. the maximum angular velocity, b. the angular position when t = 2. 24 s. B

With complete solution please. Thanks

A motor of mass M is supported by springs with an equivalent spring constant k The unbalance of its rotor is equivalent to a mass m located at a distance r from the axis of rotation. Show that when the angular velocity of the motor is wf, the amplitude of the motion of the motor is where

Chapter 19 Solutions

Vector Mechanics For Engineers

Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - A particle moves in simple harmonic motion....Ch. 19.1 - Prob. 19.3P Ch. 19.1 - Prob. 19.4P Ch. 19.1 - Prob. 19.5P Ch. 19.1 - A 20-lb block is initially held so that the...Ch. 19.1 - Prob. 19.7P Ch. 19.1 - A simple pendulum consisting of a bob attached to...Ch. 19.1 - Prob. 19.9P Ch. 19.1 - A 5-kg fragile glass vase is surrounded by packing...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

(a) The time required for the bob to return to point A.

Solution Summary: The author explains the length of the pendulum as it moves between points A and B, and the period of oscillation in this quarter.