The number of moles of electrons a battery can deliver in one hour has to be determined. Concept introduction: The Faraday’s first law of electrolysis state that the mass of the substance ( m ) deposited at any electrode is directly proportional to the charge ( Q ) passed. The mathematical form of the Fraday’s first law is written as’ m = ( Q F ) ( M Z ) Here, The symbol F is the Faraday’s constant. The symbol M is the molar mass of the substance in grams per mol. The symbol Z is the valency number of ions of the substance (electrons transferred per ion). In the simple case of constant current electrolysis, Q = I × t leading to m = ( I × t F ) ( M Z ) (1) The above formula is written in terms of the number of moles ( n ) , n = ( I × t F ) ( 1 Z ) (2) Here, t is the total time the constant current ( I ) is applied.
The number of moles of electrons a battery can deliver in one hour has to be determined. Concept introduction: The Faraday’s first law of electrolysis state that the mass of the substance ( m ) deposited at any electrode is directly proportional to the charge ( Q ) passed. The mathematical form of the Fraday’s first law is written as’ m = ( Q F ) ( M Z ) Here, The symbol F is the Faraday’s constant. The symbol M is the molar mass of the substance in grams per mol. The symbol Z is the valency number of ions of the substance (electrons transferred per ion). In the simple case of constant current electrolysis, Q = I × t leading to m = ( I × t F ) ( M Z ) (1) The above formula is written in terms of the number of moles ( n ) , n = ( I × t F ) ( 1 Z ) (2) Here, t is the total time the constant current ( I ) is applied.
Solution Summary: The author explains how the number of moles of electrons a battery can deliver in one hour is determined by the Faraday's first law of electrolysis.
The number of moles of electrons a battery can deliver in one hour has to be determined.
Concept introduction:
The Faraday’s first law of electrolysis state that the mass of the substance (m) deposited at any electrode is directly proportional to the charge (Q) passed. The mathematical form of the Fraday’s first law is written as’
m=(QF)(MZ)
Here,
The symbol F is the Faraday’s constant.
The symbol M is the molar mass of the substance in grams per mol.
The symbol Z is the valency number of ions of the substance (electrons transferred per ion).
In the simple case of constant current electrolysis, Q=I×t leading to
m=(I×tF)(MZ) (1)
The above formula is written in terms of the number of moles (n),
n=(I×tF)(1Z) (2)
Here, t is the total time the constant current (I) is applied.
(b)
Interpretation Introduction
Interpretation:
The mass of lithium oxidized under given conditions in one hour has to be calculated.
Concept introduction:
The Faraday’s first law of electrolysis state that the mass of the substance (m) deposited at any electrode is directly proportional to the charge (Q) passed. The mathematical form of the Fraday’s first law is written as’
m=(QF)(MZ)
Here,
The symbol F is the Faraday’s constant.
The symbol M is the molar mass of the substance in grams per mol.
The symbol Z is the valence number of ions of the substance (electrons transferred per ion).
In the simple case of constant current electrolysis, Q=I×t leading to
m=(I×tF)(MZ) (1)
The above formula is written in terms of the number of moles (n),
n=(I×tF)(1Z) (2)
Here, t is the total time the constant current (I) is applied.
Michael Reactions
19.52 Draw the products from the following Michael addition reactions.
1.
H&C CH
(a)
i
2. H₂O*
(b)
OEt
(c)
EtO
H₂NEt
(d)
ΕΙΟ
+
1. NaOEt
2. H₂O'
H
H
1. NaOEt
2. H₂O*
Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic.
НОН НЬ
OHd
Онс
Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
?
starting
material
target
If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
+ More...
Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
:0
T
Add/Remove step
G
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell