Explanation Figure 1 represents three charges on the corners of the equilateral triangle, separated by equal distance. Write the expression for angle from the equilateral in Figure 1. cos 30.0 ° = 15.0 cm d d = 15.0 cm cos 30.0 ° (I) Figure 2 represents net force acting on a balloon. Write the expression for angle from the triangle in Figure 2. sin θ = ( d 50.0 cm ) θ = sin − 1 ( d 50.0 cm ) (II) Use equation (I) in (II). θ = sin − 1 ( 15.0 cm / cos 30.0 ° 50.0 cm ) = sin − 1 ( 15.0 cm cos 30.0 ° × 50.0 cm ) = 20.3 ° (III) Write the expression for angle from the right-angle triangle in Figure 2. tan θ = F q m g (IV) Here, F q is the resultant force, m is the mass, and g is the acceleration due to gravity. Rearrange equation (IV). F q = m g tan θ (V) Use equation (III) in (V). F q = m g tan 20.3 ° (VI) Figure 3 represents net force acting on the balloon, due to the other charges. Write the expression for resultant force F q from the Figure 3. F q = 2 F cos 30.0 ° (VII) Here, F q is the resultant force, and F is the electrostatic force on one charge on the left of the triangle due to the due to the other charges in the opposite direction. Write the expression for electrostatic force on one charge due to the other charge from Figure 3. F = k e q 2 ( 0

Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)

5th Edition

ISBN: 9781305586871

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 19, Problem 77P

To determine

The common charge each balloon carries.

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Chapter 19, Problem 76P

Chapter 19, Problem 78P

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