Explanation Given info: The kinetic energy of the electron is 1.51 eV . The electrostatic force is given by, F e = k | q 1 | | q 2 | r 2 = k q 1 q 2 r 2 Here, F e is the electrostatic force. q 1 is the charge of electron. q 2 is the charge of proton. r is the radius of orbit. k is the coulomb’s constant. The value of k is 8.99 × 10 9 N ⋅ m 2 / C . The charge of the proton is 1.6 × 10 − 19 C and charge of electron I s − 1.6 × 10 − 19 C . The centripetal force between electron and proton is, F c = m v 2 r Here, m is the mass of the electron. v is the speed of the electron. F c is the centripetal force between electron and proton. The electrostatic force is equal to the centripetal force. F e = F c Substitute m v 2 r for F c and k q 1 q 2 r 2 for F e in above equation. k q 1 q 2 r 2 = m v 2 r r = k q 1 q 2 m v 2 (1) The kinetic energy of the electron is, K = 1 2 m v 2 (2) Here, K is kinetic energy of the electron

Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)

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ISBN: 9780134032610

Author: James S. Walker

Publisher: PEARSON

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Chapter 19, Problem 76GP

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The radius of the orbit.

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Chapter 19, Problem 75GP

Chapter 19, Problem 77GP

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Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)

Ch. 19.1 - Enhance Your Understanding (Answers given at the...Ch. 19.2 - Enhance Your Understanding (Answers given at the...Ch. 19.3 - Positive and negative charges of equal magnitude...Ch. 19.4 - Enhance Your Understanding (Answers given at the...Ch. 19.5 - The electric field lines for a system of two...Ch. 19.6 - Two conducting spheres of different radii are...Ch. 19.7 - Four Gaussian surfaces (A, B, C, D) are shown in...Ch. 19 - The fact that the electron has a negative charge...Ch. 19 - Explain why a comb that has been rubbed through...Ch. 19 - Small bits of paper are attracted to an...

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The radius of the orbit.

Solution Summary: The author explains the kinetic energy of the electron, the electrostatic force, and the centripetal force between electron and proton.

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The radius of the orbit.

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Chapter 19 Solutions