Half-life of a nuclide is given. Third life of the nuclide is to be defined and determined. Concept introduction: A process through which a unstable nuclide looses its energy due to excess of protons or neutrons is known as radioactive decay. The cause of instability of a nuclide is its inefficiency in holding the nucleus together. Half life of radioactive sample is defined as the time required for the number of nuclides to reach half of the original value. To determine: The third life of the nuclide.

Question

(11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)!

Answer 1

Question

Chapter 19, Problem 71AE

Interpretation Introduction

Interpretation: Half-life of a nuclide is given. Third life of the nuclide is to be defined and determined.

Concept introduction: A process through which a unstable nuclide looses its energy due to excess of protons or neutrons is known as radioactive decay. The cause of instability of a nuclide is its inefficiency in holding the nucleus together.

Half life of radioactive sample is defined as the time required for the number of nuclides to reach half of the original value.

To determine: The third life of the nuclide.

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