Concept explainers
(a)
Interpretation: Product obtained when the given compound undergoes hydrolysis in presence of
Concept introduction:
An enamine is a compound where the lone pair of electrons in the nitrogen atom of
Hydrolysis of enamine: Under acidic conditions, enamine reacts with water to give corresponding
Here, the bond between nitrogen and the
(b)
Interpretation: Product obtained when the given compound undergoes hydrolysis in presence of
Concept introduction:
An imine is a compound having
Hydrolysis of imine: Under acidic conditions, imine reacts with water to give corresponding ketone and primary amine.
Here, the
(c)
Interpretation: Product obtained when the given compound undergoes hydrolysis in presence of
Concept introduction:
An acetal is a compound having structural formula
Hydrolysis of acetal: Acetal treated by aqueous acid gives corresponding ketone and alcohol. An acid catalysis is required for the acetal hydrolysis.
(d)
Interpretation: Product obtained when the given compound undergoes hydrolysis in presence of
Concept introduction:
An acetal is a compound having structural formula
Hydrolysis of acetal: Acetal treated by aqueous acid gives corresponding ketone and alcohol. An acid catalysis is required for the acetal hydrolysis.

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Chapter 19 Solutions
ORGANIC CHEMISTRY-NEXTGEN+BOX (2 SEM.)
- When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)arrow_forwardCalculate the variation in the potential of the Pt/MnO4-, Mn2+ pair with pH, indicating the value of the standard potential. Data: E0 = 1.12.arrow_forwardGiven the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt. Calculate the emf of the cell as a function of pH.arrow_forward
- The decimolar calomel electrode has a potential of 0.3335 V at 25°C compared to the standard hydrogen electrode. If the standard reduction potential of Hg22+ is 0.7973 V and the solubility product of Hg2Cl2 is 1.2x 10-18, find the activity of the chlorine ion at this electrode.Data: R = 8.314 J K-1 mol-1, F = 96485 C mol-1, T = 298.15 K.arrow_forward2. Add the following group of numbers using the correct number of significant figures for the answer. Show work to earn full credit such as rounding off the answer to the correct number of significant figures. Replace the question marks with the calculated answers or write the calculated answers near the question marks. 10916.345 37.40832 5.4043 3.94 + 0.0426 ? (7 significant figures)arrow_forwardThe emf at 25°C of the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt was 612 mV. When solution X was replaced by normal phosphate buffer solution with a pH of 6.86, the emf was 741 mV. Calculate the pH of solution X.arrow_forward
- Indicate how to calculate the potential E of the reaction Hg2Cl2(s) + 2e ⇄ 2Hg + 2Cl- as a function of the concentration of Cl- ions. Data: the solubility product of Hg2Cl2.arrow_forwardHow can Beer’s Law be used to determine the concentration in a selected food sample. Provide an in-depth discussion and examples of this.arrow_forwardb) H3C- H3C Me CH 3 I HN Me H+arrow_forward
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