a) Explanation Given info: The separation between the two wires is 2.50 cm . The wires carry current in opposite direction. Current in one wire is 1.25 A and in the other is 3.50 A . Explanation: If the system of the two wires has to be in equilibrium, the repulsive force per unit length on the top wire due to the bottom wire has to be equal to the weight per unit length of the top wire. F l = μ 0 I 1 I 2 2 π d F l is the weight per unit length I 1 is the current in the one wire I 2 is the current in the second wire d is the distance between the wires μ 0 is the permeability of free space Substitute 4 π × 10 − 7 T ⋅ m ⋅ A -1 for μ 0 , 2.50 cm for d , 1.25 A for I 1 , 3 b) To determine Whether the force between the wires is attractive or repulsive.

11th Edition

ISBN: 9781305952300

Author: Raymond A. Serway, Chris Vuille

Publisher: Cengage Learning

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 19, Problem 55P

To determine

The magnitude of the force per unit length that one wire exert on the other.

To determine

Whether the force between the wires is attractive or repulsive.

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Chapter 19, Problem 54P

Chapter 19, Problem 56P

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Chapter 19 Solutions

College Physics

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The magnitude of the force per unit length that one wire exert on the other.

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The magnitude of the force per unit length that one wire exert on the other.

Whether the force between the wires is attractive or repulsive.

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Chapter 19 Solutions