Concept explainers
Interpretation: The voltaic cell representation, anode and cathode reactions, the electrons flow and half reactions should be discussed.
Concept introduction: Oxidation happens when an atom loses its electrons; it undergoes oxidation which is an increase in the charge. There are three conditions for oxidation:
1. Addition of oxygen.
2. Removal of hydrogen.
3. Loss of electrons.
Reduction happens when an atom gains electrons and has a decrease in oxidation state which decreases the charge on the atom. There are three conditions of reduction:
1. Removal of oxygen.
2. Addition of hydrogen.
3. Gain of electrons.
Redox reactions are the reactions in which oxidation and reduction both takes place simultaneously.
Cell reaction consists of anode and cathode which is divided by a salt bridge.
At anode: oxidation takes place.
At cathode: reduction takes place.
Electrons flow from anode to cathode.
Voltaic cell is an
To write: The voltaic cell reaction, anode and cathode reaction, and the direction of electron flow.

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Chapter 19 Solutions
CHEM: STRUC & PROP (LL) VOL 2 >C PKG<
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- I apologize, but the app is not allowing me to post the other 4 pictures of the thermodynamics chart. But I believe the values are universal. Please help!arrow_forwardCalculating the pH of a salt solution Calculate the pH at 25 °C of a 0.29M solution of potassium butanoate (KC3H,CO2). Note that butanoic acid (HC3H,CO2) is a weak acid with a pKa of 4.82. Round your answer to 1 decimal place. pH = -0 Х olo 18 Ararrow_forward: At a certain temperature, the equilibrium constant K for the following reaction is 1.58 × 10-12 N2(g) + O2(g) = 2 NO(g) Use this information to complete the following table. Suppose a 38. L reaction vessel is filled with 0.93 mol of N2 and 0.93 mol of O2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little N2 and O2. There will be very little NO. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 NO(g) N2(9)+02(9) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 N2(9)+302(g) 6 NO(g) Neither of the above is true. K = ☐ K = ☐ ☐ X10 Х D ? 000 18 Ar Barrow_forward
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