Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN: 9781305084766
Author: Saeed Moaveni
Publisher: Cengage Learning
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Chapter 19, Problem 29P
To determine
Calculate the probability that a car would need engine maintenance between 70000 and 90000 miles.
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3. What is the maximum allowable load that can be applied to the pile shown below? :
Qall = ?
G.W.T.
45'
Soft Clay:
Ysat 100 pcf
Cu = 500 psf, ou = 0°
Clay Shale:
Qu(lab) 24,000 psi
o' = 15°
Driven Steel H-Pile:
1/2" thick steel web
& flanges
(soil plugged)
-10".
I
Note: Pile & soil profile
are not drawn to scale
Please use the approach outlined in Das 12.16 and an Allowable Stress Design (ASD)
approach for your analysis. Use a factor of safety = 3 for design, neglect any effect that shaft
resistance has on pile capacity, and neglect the effect of the weight of the pile in your
analysis.
2. Calculate the ultimate load carrying capacity of the pile tip driven into the soil profile shown
below:
G.W.T.
Qapp
40'
Soft Clay:
Ysat 100 pcf
Cu 500 psf, ₁ = 0°
4c+4
Poorly Graded Sand (SP):
Ysat = 125 pcf
Q₁ = ?
c' = 0, ' = 35°
Driven Steel Pipe Pile:
Outside Diameter = 2'
Inside Diameter = 1'11"
Hollow (soil plugged)
Note: Pile & soil profile
are not drawn to scale
For this problem, please calculate N₁* using both the bearing capacity theory approach and using
standard design charts. Compare the values that result from these two approaches. Please use
only the Nq* from bearing capacity theory for the remainder of your calculations.
Design a fully restrained BFP moment connection to support the factored bending
moment of 1,200 kN·m and factored shear force of 95 kN due to wind and gravity
loads. Use 90mm spacing between the bolts, and 40mm edge spacing. The steel
grade is A992 for the W920 × 201 beam and W840 × 359 column and A36 for the
steel plate (30 mm thick). Use FEXX = 450 MPa electrodes and 20mm A490 bolts
(threads included) for the flange plate (Fr= 457 MPa), 16mm A307 bolts for the
shear tab (Fnv = 165 MPa).
Steel Section Properties
W920 × 201
W840 × 359
D₁ = 904 mm bf = 305 mm tf = 20.1 mm tw = 15.2 mm
d = 869 mm bf = 404 mm tf = 35.6 mm tw = 21.1 mm
Summary of answer:
Flange Plate:
bPL =
tPL
=
No. of Bolts: Flange bolt =
Thickness of fillet weld on shear tab:.
Shear tab =
Chapter 19 Solutions
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
Ch. 19.3 - Prob. 1BYGCh. 19.3 - Prob. 2BYGCh. 19.3 - Prob. 3BYGCh. 19.3 - VocabularyState the meaning of the following...Ch. 19.5 - Prob. 1BYGCh. 19.5 - Prob. 2BYGCh. 19.5 - Prob. 3BYGCh. 19.5 - Prob. 4BYGCh. 19.5 - Prob. 5BYGCh. 19.5 - Prob. BYGV
Ch. 19 - The scores of a test for an engineering class of...Ch. 19 - Prob. 2PCh. 19 - For Problem 19.1, using Equations (19.1) and...Ch. 19 - Prob. 4PCh. 19 - Prob. 5PCh. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - Prob. 9PCh. 19 - Prob. 12PCh. 19 - Prob. 13PCh. 19 - Prob. 14PCh. 19 - Prob. 15PCh. 19 - Imagine that you and four of your classmates have...Ch. 19 - Prob. 17PCh. 19 - Prob. 18PCh. 19 - Prob. 19PCh. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - Prob. 22PCh. 19 - Prob. 23PCh. 19 - Prob. 24PCh. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - Prob. 28PCh. 19 - Prob. 29PCh. 19 - Prob. 30PCh. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - Prob. 33PCh. 19 - Prob. 34PCh. 19 - Prob. 35PCh. 19 - Prob. 36PCh. 19 - Prob. 37PCh. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - Prob. 40PCh. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - Prob. 43PCh. 19 - Prob. 44PCh. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - You are to write down on a piece of paper the...Ch. 19 - Prob. 49PCh. 19 - Prob. 50P
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