STATS:DATA+MODELS-W/DVD
4th Edition
ISBN: 9780321986498
Author: DeVeaux
Publisher: PEARSON
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Chapter 19, Problem 28E
a.
To determine
State the null and alternative hypotheses.
b.
To determine
State the conditions and requirements of the hypotheses test.
Find the P-value.
c.
To determine
Check whether the acceptance rate was consistent with the national average.
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2.2, 13.2-13.3)
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The accompanying table contains the data for the amounts (in oz) in cans of a certain soda. The cans are labeled to indicate that the contents are 20 oz of soda. Use the sign test and
0.05 significance level to test the claim that cans of this soda are filled so that the median amount is 20 oz. If the median is not 20 oz, are consumers being cheated?
Click the icon to view the data.
What are the null and alternative hypotheses?
OA. Ho: Medi
More Info
H₁: Medi
OC. Ho: Medi
H₁: Medi
Volume (in ounces)
20.3
20.1
20.4
Find the test stat
20.1
20.5
20.1
20.1
19.9
20.1
Test statistic =
20.2
20.3
20.3
20.1
20.4
20.5
Find the P-value
19.7
20.2
20.4
20.1
20.2
20.2
P-value=
(R
19.9
20.1
20.5
20.4
20.1
20.4
Determine the p
20.1
20.3
20.4
20.2
20.3
20.4
Since the P-valu
19.9
20.2
19.9
Print
Done
20 oz
20 oz
20 oz
20 oz
ce that the consumers are being cheated.
T
Teenage obesity (O), and weekly fast-food meals (F), among some selected Mississippi teenagers are:
Name Obesity (lbs) # of Fast-foods per week
Josh
185
10
Karl
172
8
Terry
168
9
Kamie
Andy
204
154
12
6
(a) Compute the variance of Obesity, s²o, and the variance of fast-food meals, s², of this data. [Must show full work].
(b) Compute the Correlation Coefficient between O and F. [Must show full work].
(c) Find the Coefficient of Determination between O and F. [Must show full work].
(d) Obtain the Regression equation of this data. [Must show full work].
(e) Interpret your answers in (b), (c), and (d). (Full explanations required).
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The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4.
Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?
Chapter 19 Solutions
STATS:DATA+MODELS-W/DVD
Ch. 19.2 - 1. A research team wants to know if aspirin helps...Ch. 19.2 - 2. An allergy drug has been tested and found to...Ch. 19.2 - 3. The new drug is tested and the P-value is...Ch. 19.5 - 6. A bank is testing a new method for getting...Ch. 19.5 - Prob. 5JCCh. 19.5 - Prob. 6JCCh. 19 - Prob. 1ECh. 19 - 2. Psychic A friend of yours claims to be psychic....Ch. 19 - Prob. 5ECh. 19 - Prob. 6E
Ch. 19 - Prob. 9ECh. 19 - Prob. 10ECh. 19 - Prob. 11ECh. 19 - 16. More hypotheses Write the null and alternative...Ch. 19 - Prob. 13ECh. 19 - Prob. 14ECh. 19 - Prob. 15ECh. 19 - 20. Cars A survey investigating whether the...Ch. 19 - Prob. 17ECh. 19 - Prob. 18ECh. 19 - Prob. 19ECh. 19 - Prob. 20ECh. 19 - Prob. 21ECh. 19 - Prob. 22ECh. 19 - Prob. 23ECh. 19 - 28. Educated mothers The National Center for...Ch. 19 - Prob. 25ECh. 19 - Take the offer II We saw in Chapter 16, Exercise...Ch. 19 - Prob. 29ECh. 19 - Prob. 30ECh. 19 - Prob. 31ECh. 19 - Prob. 32ECh. 19 - Prob. 33ECh. 19 - Prob. 34ECh. 19 - Prob. 35ECh. 19 - 38. Jury Census data for a certain county show...Ch. 19 - Prob. 37ECh. 19 - Prob. 38ECh. 19 - Prob. 39ECh. 19 - Prob. 40ECh. 19 - 43. John Wayne Like a lot of other Americans, John...Ch. 19 - Prob. 42ECh. 19 - Prob. 3ECh. 19 - Prob. 4ECh. 19 - Prob. 7ECh. 19 - Prob. 8ECh. 19 - Prob. 27ECh. 19 - Med school 2013 According to the Association of...
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- Suppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forwardA random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forwardSuppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forward
- Is it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forwardTines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forwardBased on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forward
- A 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forwardDescribe the situation in which Fisher’s exact test would be used?(ii) When do we use Yates’ continuity correction (with respect to contingencytables)?[2 Marks] 2. Investigate, checking the relevant assumptions, whether there is an associationbetween age group and home ownership based on the sample dataset for atown below:Home Owner: Yes NoUnder 40 39 12140 and over 181 59Calculate and evaluate the effect size.arrow_forward
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