Chapter 19, Problem 26QAP

Interpretation Introduction

(a)

Interpretation:

To write the balanced equation of alpha decay of the given nuclide ²³⁴ _{9 2} U.

Concept Introduction:

The radioactive decay is also known as nuclear transformation. The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Alpha decay is the decay in which mass number is decreases by 4 and atomic number is decreases by 2.

Interpretation Introduction

(b)

Interpretation:

To write the balanced equation of alpha decay of the given nuclide ²²² _{8 6} Rn.

Concept Introduction:

The radioactive decay is also known as nuclear transformation. The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Alpha decay is the decay in which mass number is decreases by 4 and atomic number is decreases by 2.

Interpretation Introduction

(c)

Interpretation:

To write the balanced equation of alpha decay of the given nuclide ¹⁶² _{7 5} Re.

Concept Introduction:

The radioactive decay is also known as nuclear transformation. The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Alpha decay is the decay in which mass number is decreases by 4 and atomic number is decreases by 2.