The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained. Concept Introduction: Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

H HgSO4, H2O H2SO4

12. Choose the best diene and dienophile pair that would react the fastest. CN CN CO₂Et -CO₂Et .CO₂Et H3CO CO₂Et A B C D E F

(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.

Answer 2

Question

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Answer 6

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Answer 7

Chapter 19, Problem 1Q

Interpretation Introduction

Interpretation:

The reason for 2-bromobutane to react faster than 2-chlorobutane in the test ofsilver nitrate with ethanol and NaI with acetone needs to be explained.

Concept Introduction:

Alkyl halides have halogen group as the functional group which can substitute with other groups to give substitutional reactions. In the nucleophilic substitution reactions, the reactivities of the alkyl halides depends on two important factors such as reaction conditions and substrate structure.

Answer 8

Expert Solution & Answer

Answer to Problem 1Q

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information:

Both 2-bromobutane and 2-chlorobutane give positive test with silver nitrate with ethanol and KI with acetone.

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane. The −Br leaving group is a weak base therefore it is a good leaving group compare to −Cl which is a stronger base and weak leaving group.

Hence 2-bromobutane reacts faster than 2-chlorobutane with silver nitrate with ethanol and NaI with acetone as both are substitution reactions that replace −Cl and −Br with −I and –NO3.

Answer 12

Conclusion

In 2-bromobutane, -Br is a better leaving group than −Cl therefore it reacts faster than 2-chlorobutane.

Answer 13

Ch. 19 - Prob. 1Q Ch. 19 - Prob. 2Q Ch. 19 - Prob. 3Q Ch. 19 - Prob. 4Q Ch. 19 - Prob. 5Q Ch. 19 - Prob. 6Q

Videos

Answer to Problem 1Q

Explanation of Solution

Want to see more full solutions like this?

Chapter 19 Solutions