
Concept explainers
Parameters and hypotheses For each of the following situations, define the parameter (proportion or mean) and write the null and alternative hypotheses in terms of parameter values. Example: We want to know if the proportion of up days in the stock market is 50%. Answer: Let p = the proportion of up days. H0: p = 0.5 vs. HA: p ≠ 0.5.
- a) A casino wants to know if their slot machine really delivers the 1 in 100 win rate that it claims.
- b) Last year, customers spent an average of $35.32 per visit to the company’s website. Based on a random sample of purchases this year, the company wants to know if the mean this year has changed.
- c) A pharmaceutical company wonders if their new drug has a cure rate different from the 30% reported by the placebo.
- d) A bank wants to know if the percentage of customers using their website has changed from the 40% that used it before their system crashed last week.
a.

Define the parameter.
State the null and alternative hypotheses.
Answer to Problem 1E
The parameter is p, which is defined as the probability of winning on a slot machine.
The test hypotheses are given below:
Null hypothesis:
Alternative hypothesis:
Explanation of Solution
Justification:
Parameter:
Any statistical measure based on all units in the population is called Parameter.
The study based on the casino wants to identify the probability of winning on a slot machine.
In the given situation, the parameter of interest is p, which is defined as the probability of winning on a slot machine.
Hypotheses:
The test hypotheses are given below:
Null hypothesis:
That is, the proportion of winning on a slot machine is 0.01
Alternative hypothesis:
That is, the proportion of winning on a slot machine is different from 0.01.
b.

Define the parameter.
State null and alternative hypothesis.
Answer to Problem 1E
The parameter is
The test hypotheses are:
Null hypothesis:
Alternative hypothesis:
Explanation of Solution
Justification:
The data represents the amount spent on purchase by the customer.
In the given situation, the parameter of interest is
The test hypotheses are given below:
Null hypothesis:
That is, the average amount spent on purchase per customer in a year is $35.32.
Alternative hypothesis:
That is, the average amount spent on purchase per customer in a year is different from $35.32.
c.

Define the parameter.
State null and alternative hypothesis.
Answer to Problem 1E
The parameter is p, which is defined as the percentage of patients cured by new drug.
The test hypotheses are given below:
Null hypothesis:
Alternative hypothesis:
Explanation of Solution
Justification:
The data represents the effect of new drug on patients by pharmaceutical company.
In the given situation, the parameter of interest is p, which is defined as the percentage of patients cured by new drug.
The test hypotheses are given below:
Null hypothesis:
That is, the percentage of patients cured by new drug is 0.30.
Alternative hypothesis:
That is, the percentage of patients cured by new drug is different from 0.30.
d.

Define the parameter.
State null and alternative hypothesis.
Answer to Problem 1E
The parameter is p, which is defined as the percentage of Customers using the website of bank.
The test hypotheses are given below:
Null hypothesis:
Alternative hypothesis:
Explanation of Solution
Justification:
A bank wants to identify the proportion of customers using the bank’s website.
In the given situation, the parameter of interest is p, which is defined as the percentage of Customers using the website of bank.
The test hypotheses are given below:
Null hypothesis:
That is, the percentage of Customers using the website of bank is 40%.
Alternative hypothesis:
That is, the percentage of Customers using the website of bank is different from 40%.
Want to see more full solutions like this?
Chapter 19 Solutions
Intro Stats
- ans c plsarrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES SCOTCEN POLL OF POLLS SHOULD SCOTLAND BE INDEPENDENT? NO 52% YES 58% LIVE CAW NAS & 28.30 HAS KILLED MORE THAN 2,600 IN WEST AFRICA, WORLD HEALTH ORG. BROOKEBCNNarrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES PRESIDENTIAL PREFERENCES RODOLFO CARTER 3% (+2pts) EVELYN MATTHEI 22% (+6pts) With the exception of President Boric, could you tell me who you would like to be the next president of Chile? CAMILA VALLEJO 4% (+2pts) JOSÉ ANTONIO KAST 19% (+5pts) MICHELLE BACHELET 6% (+1pts)arrow_forward
- Critically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES 13% APPROVE 4% DOESN'T KNOW DOESN'T RESPOND 5% NEITHER APPROVES NOR DISAPPROVES 78% DISAPPROVES SURVEY PRESIDENTIAL APPROVAL DROPS TO 13%arrow_forwardPlease help with this following question I'm not too sure if question (a) and (b) are correct and not sure how to calculate (c) The csv data is below "","New","Current" "1","67",66 "2","77",73 "3","76",73 "4","76",76 "5","77",79 "6","84",76 "7","71",78 "8","84",72 "9","73",76 "10","71",73 "11","72",77 "12","70",72 "13","75",72 "14","84",71 "15","77",73 "16","65",72 "17","69",73 "18","71",73 "19","79",71 "20","75",78 "21","76",69 "22","73",74 "23","76",71 "24","64",74 "25","81",78 "26","79",76 "27","70",77 "28","79",71 "29","84",73 "30","79",69 "31","69",72 "32","81",76 "33","77",70 "34","77",71 "35","71",69 "36","67",72 "37","70",76 "38","77",73 "39","82",73 "40","72",73arrow_forwardPlease help me answer the following question(c) A previous study found that 15% of nurses reported participating in mental health support programs.From the 96% found in (b) , can you conclude that proportion of nurses reported participating in mental health support programs p(current), has changed from the previous study?(Yes/No) because the confidence interval in (b) (captures/does not capture) 15%.(d) Refer to your answer in (b) : The Alberta Nurses Association expects that not more than 23 % of nurses will participate in the survey on mental health support programs. Given the result in part (b) can we conclude that this expectation is reasonable?(Yes/No) because the (upper bound/lower bound) of the 96% confidence interval is (less than/not less than/greater than) 23%. The Alberta Nursing Association conducts an annual survey to estimate the proportion of nurses who participate in mental health support programs. The most recent application of this survey involved a random sample of…arrow_forward
- Please help me solve this questionThis is what was in the csv file:"","Diabetic","Heart Disease""1",32644,30646"2",789,1670"3",12802,36274"4",2177,5011"5",1910,3300"6",3320,4256"7",61425,39053"8",19768,28635"9",19502,39546"10",5642,12182"11",107864,152098"12",29918,60433"13",2397,3550"14",41559,34705"15",49169,57948"16",72853,83100"17",2155,2873"18",140220,134517"19",28181,26212"20",18850,38637"21",69564,68582"22",13897,12613"23",6868,9138"24",9735,4767"25",12102,13447"26",36571,50010"27",44665,55141"28",26620,33970"29",25525,29766"30",14167,20206Q(b) From this, the relationship between these two variables is (non-existent/positive/negative) . I can categorize this relationship as being (strong/weak/moderate).Q(c) Drop down is (+/-)Q(d) Drop downs in order are __% of the (average/median/variation/standard deviation) in the (the number of people diagnosed with heart disease/the number of people diagnosed with diabetes)−variable can be explained by its (linear relationship/relationship)…arrow_forwardPlease help me answer the following question The drop down for question (e, f, and g) is (YES/NO) Based on the P-value above, the assumption of equal variances among the four machines (Is Met/Is Not Met) Based on the data, the average fill for machine 3 is (statistically lower than/statistically higher than/the same as/not statistically different than/statistically different than/Hard to say then when comparing to/Refuse to say when comparing to) machine 1.arrow_forwardBusiness Discussarrow_forward
- 1 for all k, and set o (ii) Let X1, X2, that P(Xkb) = x > 0. Xn be independent random variables with mean 0, suppose = and Var Xk. Then, for 0x) ≤2 exp-tx+121 Στ k=1arrow_forwardLemma 1.1 Suppose that g is a non-negative, non-decreasing function such that E g(X) 0. Then, E g(|X|) P(|X|> x) ≤ g(x)arrow_forwardProof of this Theorem Theorem 1.2 (i) Suppose that P(|X| ≤ b) = 1 for some b > 0, that E X = 0, and set Var X = o². Then, for 0 0, P(X > x) ≤ e−1x+1²², P(|X|> x) ≤ 2e−x+1² 0²arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL



