Chapter 19, Problem 19D.3AE

Interpretation Introduction

Interpretation:

The current density in the electrolysis of $1.0MNaOH\left(aq\right)$ at $0.60V$ has to be calculated.

Concept Introduction:

When the over potential is large and positive $\left(\eta \ge 0.12V\right)$, the anodic process is dominant. The current density is given by

  $\text{J}\text{=}{\text{J}}_{\text{0}}{\text{e}}^{\text{(1-α)}}{}^{\text{fη}}$

When the over potential is large and negative $\left(\eta \le -0.12V\right)$, the cathodic process is dominant. The current density is given by

  $\text{J}\text{=}{\text{J}}_{\text{0}}{\text{e}}^{-\alpha }{}^{\text{fη}}$