Chapter 19, Problem 19.60SP

Interpretation Introduction

Interpretation:

The fraction of strontium-90 remaining after 3 half-lives should be determined.

Concept Introduction:

To determine the decay constant for strontium,

  $k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}$

where $t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$ is half-life
K is the decay constant

  $k=\frac{2.303}{t}\log \frac{A_o}{A_t}$

where t is the time period

  $A_t$ is a concentration of the nuclei at time = t

  $A_o$ is the initial concentration of the nuclei

Interpretation Introduction

Interpretation:

Value of the decay constant for strontium-90 should be determined.

Concept Introduction:

To determine the decay constant for strontium,

  $k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}$

Where $t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$ is half-life
K is the decay constant

  $k=\frac{2.303}{t}\log \frac{A_o}{A_t}$

where t is the time period

  $A_t$ is a concentration of the nuclei at time = t

  $A_o$ is the initial concentration of the nuclei

Interpretation Introduction

Interpretation:

Time in years required for 99 % of the strontium-90 to disappear.

Concept Introduction:

To determine the decay constant for strontium,

  $k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}$

Where $t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}$ is half-life
K is the decay constant

  $k=\frac{2.303}{t}\log \frac{A_o}{A_t}$

where t is the time period

  $A_t$ is a concentration of the nuclei at time = t

  $A_o$ is the initial concentration of the nuclei