![EP FUND.OF GENERAL,ORG...-MOD.MASTERING](https://www.bartleby.com/isbn_cover_images/9780134326061/9780134326061_largeCoverImage.gif)
(a)
Interpretation:
The type of enzyme regulation occurs in the pathway which stops at the first enzyme in the multistep process of the conversion of glucose to pyruvate should be determined.
Concept Introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Feedback control: The pathways which are dependent on a series of consecutive reactions in which the product of one reaction is the reactant for the next and these pathways are subjected to feedback control, which occurs when the result of a process feeds information back to affect the beginning process.
(b)
Interpretation:
The type of enzyme regulation occurs when Sarin covalently binds to acetylcholinesterase should be determined.
Concept Introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Reversible Competitive inhibition: It is a type of inhibition occurs when the inhibitor resembles very much to the substrate and thus prevents the substrate binding.
Reversible uncompetitive inhibition: It is a type of enzyme regulation in which an inhibitor binds reversibly to the enzyme-substrate complex and thereby blocking the binding of the second substrate to the binding site.
Irreversible competitive inhibition: It is a type of inhibition in which an inhibitor forms covalent bonds to the active site and thereby permanently blocking it.
(c)
Interpretation:
The type of enzyme regulation occurs when Lactase is not produced in the adult should be determined.
Concept Introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Enzyme inhibitors: The substance which slows or stops the action of an enzyme is called enzyme inhibitors.
It can be used as drugs and an example is AZT which is used to treat HIV.
Enzyme regulation by genetic control:
It is a type of control by which regulation of enzyme activity is done by the control of the synthesis of enzymes.
(d)
Interpretation:
The type of enzyme regulation occurs when the conversion of isocitrate to
Concept Introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Irreversible competitive inhibition: It is a type of inhibition in which an inhibitor forms covalent bonds to the active site and thereby permanently blocking it.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 19 Solutions
EP FUND.OF GENERAL,ORG...-MOD.MASTERING
- Do schwann cells produce or act as myelin in the peripheral nervous system? I know that they encase and wrap around axons, but where does the myelin come into play?arrow_forwardThe enzyme lactate dehydrogenase (LDH) catalyzes the conversion of pyruvate to lactatein skeletal muscle cells using NAD/NADH during anaerobic “balanced” fermentation.Answer the following questions about this reaction. (a) Write out the two reductive half reactions and indicate the E ̊' for each half reaction. Write out the full balanced reaction for the pyruvate to lactate rxn and indicate the ∆E ̊' for the reaction. (b) What is the free energy change under standard state conditions for thisreaction? Which direction is spontaneous?(c) Assume that in skeletal muscle cells the ratio of [NAD+] to [NADH] is 100, and that the[pyruvate] = 0.40 mM and [lactate] = 4.0 mM. What is the free energy change (∆G')for the conversion of pyruvate to lactate? Indicate the direction in which the reactionis spontaneous under these cellular conditions.arrow_forwardWhy did the authors worry about the temperature-dependent solubility of the carriers in thebilayer? How did the authors determine whether the effect of freezing the lipid bilayer wasto decrease the solubility of the carriers (nonactin and valinomycin) or whether the effectwas to impair their ability to diffuse through the membrane (decrease their mobility)?arrow_forward
- Kranse et. al. measured the temperature dependence of conductance using membranescontaining the phospholipids glyceryl dipalmitate and glyceryl distearate. Describe themodifications in membrane content that you would employ to: (a) shift the temperature of the phase transition (b) make the ion conductance curve for valinomycin andnonactin more like that of gramicidinarrow_forwardObtain the sequence for the 5-HT receptor HTR1A and generate a hydropathy plot usingthe ExPASY tool ProtScale, the appropriate window, and the Kyte-Doolittle weightingalgorithm. How many transmembrane domains are present in this receptor? Attach yourhydropathy plot to your assignment.arrow_forwardCompare and contrast the structural features of the ion carrier valinomycin with those of achannel former like gramicidin. How does structural information help explain the mechanismby which these molecules conduct ions across membranes?arrow_forward
- A typical integral membrane protein has a stretch (or stretches) of ~20 hydrophobic aminoacids that form an α-helix that spans the bilayer (as is found in membrane proteins such asglycophorin A and bacteriorhodopsin). Compare and contrast the molecular and structural features of gramicidin with a membrane-spanning α-helix. Explain how gramicidin can forman ion channel when a typical membrane-spanning α-helix cannot (eg, glycophorin A).arrow_forwardThe titration curve of alanine shows the ionization of two functional groups with pK values of 2.34 and 9.69, corresponding to the ionization of the carboxyl and the protonated amino groups, respectively. The titration of di-, tri-, and larger oligopeptides of alanine also shows the ionization of only two functional groups, although the experimental pK values are different. The table summarizes the trend in pK values. Amino acid or peptide Ala Ala-Ala pKj pk₂ 2.34 9.69 3.12 8.30 Ala-Ala-Ala 3.39 8.03 Ala-(Ala)-Ala, n ≥ 4 3.42 7.94 Modify the molecules to show the oligopeptide Ala-Ala-Ala. You can modify the molecules by moving, adding, deleting, or changing atoms, bonds, or charges. C Select c Draw Templates More H с N 0 S Cl H H | | || H CH3 H CH, H CH₂ Complete the statements about the the pK, values of the Ala-Ala-Ala oligopeptide. The pK₁ value of 3.39 is associated with the -COO group of Ala-Ala-Ala. The pK2 value of 8.03 is associated with the -NH group of Ala-Ala-Ala. Erase Q2 Q…arrow_forwardFacts from the bacterium mals and to dept kan apa in a peptide with antidic properties. This peptide complex with the call membrance of other hacterial species, leading in bacterial death The structure of the peptide has been determined from (a) Cmplete acid hydes of the peptide, followed by amino acid analys, yielded quiar anunt of Lan, Om, Pfx, Prxa, and Wall Cmtiti, an amino acid od prosentin pockets but present in some peptides. Com has the tracture H *H,N-CH-CH-CH, -C- COO (b) The weight of the peptide in approximately 1,200 Th (c) The peptide failed to undergo hydrolysis when treated with the Hydrolysis of the carbonyl-terminal residue of a polypeptide une "NH, the year. This call there Pro or the police does not contain a froz (d) Treatment of the peptide with 1-haw-2,4-dicherer (11N1), followed by complete hydrolysis and ched only from and the derivative NO, Н ON NHCHI CH, CH, C coo +NH, (Hint: The 2,4-diphenyl derivative involves the amino group of a side chain rather than the…arrow_forward
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxBiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
- Human Physiology: From Cells to Systems (MindTap ...BiologyISBN:9781285866932Author:Lauralee SherwoodPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781947172517/9781947172517_coverImage_Textbooks.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577206/9781305577206_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285866932/9781285866932_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337392938/9781337392938_smallCoverImage.gif)