Chapter 19, Problem 119AP

Interpretation Introduction

Interpretation:

The given equation is to be balanced in acidic solution and the mass percent of oxalic acid present in the given sample is to be calculated.

Concept introduction:

The following are the steps to be followed to balance the chemical equation in acidic medium:

Step 1: Write the skeleton equation.

Step 2: Separate the unbalanced reaction into half reactions.

Step 3: Balance the atoms other than oxygen and hydrogen in the half reactions.

Step 4: Balance the oxygen atoms in the half reactions by adding water molecules to the deficient side.

Step 5: After balancing oxygen atoms, balance hydrogen atoms by adding protons (${\text{H}}^{\text{+}}$) to the deficient side.

Step 6: Balance the charge so that both sides have the same total charge by adding electrons to the more positive side to equal the less positive side of the half reaction.

Step 7: Make the electron gain equivalent to the electron loss in the oxidation half reactions and reduction half reactions.

Step 8: Combine the two half reactions.

Step 9: Remove the chemical species from both sides of the similar kind if any and write the simplified chemical equation.

The ratio of the number of moles of solute to the volume of solution in liter is termed as molarity of the solution and it is given by the following relation:

$\text{Molarity}=\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{L}}$

The mass percent of a substance can be determined by the relation mentioned below:

$\text{Mass}\text{percent}\text{of}\text{a}\text{substance}=\frac{\text{Mass}\text{of}\text{substance}}{\text{Total}\text{mass}\text{of}\text{solution}}\text{×}\text{100}$