The time of fuel cell operate before the hydrogen runs out has to be determined. Concept introduction: The Faraday’s first law of electrolysis state that the mass of the substance ( m ) deposited at any electrode is directly proportional to the charge ( Q ) passed. The mathematical form of the Fraday’s first law is written as’ m = ( Q F ) ( M Z ) Here, The symbol F is the Faraday’s constant. The symbol M is the molar mass of the substance in grams per mol. The symbol Z is the valency number of ions of the substance (electrons transferred per ion). In the simple case of constant current electrolysis, Q = I × t leading to m = ( I × t F ) ( M Z ) (1) The above formula is written in terms of the number of moles ( n ) , n = ( I × t F ) ( 1 Z ) (2) Here, t is the total time the constant current ( I ) is applied. The ideal gas law is written as, PV = nRT (3) Here, The pressure of the gas is P . The volume of the gas container is V . The number of moles of gas particles is n . The temperature is T . The gas constant is R .
The time of fuel cell operate before the hydrogen runs out has to be determined. Concept introduction: The Faraday’s first law of electrolysis state that the mass of the substance ( m ) deposited at any electrode is directly proportional to the charge ( Q ) passed. The mathematical form of the Fraday’s first law is written as’ m = ( Q F ) ( M Z ) Here, The symbol F is the Faraday’s constant. The symbol M is the molar mass of the substance in grams per mol. The symbol Z is the valency number of ions of the substance (electrons transferred per ion). In the simple case of constant current electrolysis, Q = I × t leading to m = ( I × t F ) ( M Z ) (1) The above formula is written in terms of the number of moles ( n ) , n = ( I × t F ) ( 1 Z ) (2) Here, t is the total time the constant current ( I ) is applied. The ideal gas law is written as, PV = nRT (3) Here, The pressure of the gas is P . The volume of the gas container is V . The number of moles of gas particles is n . The temperature is T . The gas constant is R .
Solution Summary: The author explains the Faraday's first law of electrolysis, which states that the mass of the substance is directly proportional to the charge passed.
Definition Definition Law that is the combined form of Boyle's Law, Charles's Law, and Avogadro's Law. This law is obeyed by all ideal gas. Boyle's Law states that pressure is inversely proportional to volume. Charles's Law states that volume is in direct relation to temperature. Avogadro's Law shows that volume is in direct relation to the number of moles in the gas. The mathematical equation for the ideal gas law equation has been formulated by taking all the equations into account: PV=nRT Where P = pressure of the ideal gas V = volume of the ideal gas n = amount of ideal gas measured in moles R = universal gas constant and its value is 8.314 J.K-1mol-1 T = temperature
Chapter 19, Problem 113SCQ
Interpretation Introduction
Interpretation:
The time of fuel cell operate before the hydrogen runs out has to be determined.
Concept introduction:
The Faraday’s first law of electrolysis state that the mass of the substance (m) deposited at any electrode is directly proportional to the charge (Q) passed. The mathematical form of the Fraday’s first law is written as’
m=(QF)(MZ)
Here,
The symbol F is the Faraday’s constant.
The symbol M is the molar mass of the substance in grams per mol.
The symbol Z is the valency number of ions of the substance (electrons transferred per ion).
In the simple case of constant current electrolysis, Q=I×t leading to
m=(I×tF)(MZ) (1)
The above formula is written in terms of the number of moles (n),
n=(I×tF)(1Z) (2)
Here, t is the total time the constant current (I) is applied.
Please help me answer these three questions. Required info should be in data table.
Draw the major organic substitution product or products for (2R,3S)-2-bromo-3-methylpentane reacting with the given
nucleophile. Clearly drawn the stereochemistry, including a wedged bond, a dashed bond and two in-plane bonds at each
stereogenic center. Omit any byproducts.
Bri
CH3CH2O-
(conc.)
Draw the major organic product or products.
Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH.
How many mL of NaOH are needed to reach the first equivalence point?
How many mL of NaOH are needed to reach the second equivalence point?
Chapter 19 Solutions
OWLv2 6-Months Printed Access Card for Kotz/Treichel/Townsend's Chemistry & Chemical Reactivity, 9th, 9th Edition
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell