Explanation M n O 4 − ( a q ) + Z n ( s ) → M n 2 + ( a q ) + Z n 2 + ( a q ) Step1: Separate the overall reaction into two half-reactions: one for oxidation and one forreduction. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) → M n + 2 ( a q ) Step2: Balance the main elements excluding H, O. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) → M n + 2 ( a q ) Step3: Balance the H, O. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) + 8 H + ( a q ) → M n + 2 ( a q ) + 4 H 2 O ( l ) In these half-reactions, all elements are balanced including H, O. Hence, in the next step we need to balance the charge. Step4: Balance each half-reaction with respect to charge by adding electrons. For oxidation Z n ( s ) → Z n + 2 ( a q ) + 2 e − For reduction M n O 4 − ( a q ) + 8 H + ( a q ) + 5 e − → M n + 2 ( a q ) + 4 H 2 O ( l ) Step5: Make the number of electrons in both half-reactions equal by multiplying one or both half-reactions by a small whole number. For oxidation 5 × [ Z n ( s ) → Z n + 2 ( a q ) + 2 e − ] For reduction 2 × [ M n O 4 − ( a q ) + 8 H + ( a q ) + 5 e − → M n + 2 ( a q ) + 4 H 2 O ( l ) ] By adding these two reactions, we have 2 M n O 4 − ( a q ) + 16 H + ( a q )

Chemistry: A Molecular Approach Selected Solutions Manual, Books a la Carte Edition

4th Edition

ISBN: 9780134554259

Author: Nivaldo J. Tro

Publisher: PEARSON

See similar textbooks

Question

Chapter 19, Problem 105E

Interpretation Introduction

To balance the equation and determining the volume of a 0.500 M KMnO4 solution required to completely react with 2.85g of Zn.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 19, Problem 104E

Chapter 19, Problem 106E

Students have asked these similar questions

In the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,

For a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.

Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0

Chapter 19 Solutions

Chemistry: A Molecular Approach Selected Solutions Manual, Books a la Carte Edition

Ch. 19 - Prob. 1SAQ Ch. 19 - Q2. Which statement is true for voltaic cells? a)...Ch. 19 - Prob. 3SAQ Ch. 19 - Prob. 4SAQ Ch. 19 - Prob. 5SAQ Ch. 19 - Prob. 6SAQ Ch. 19 - Prob. 7SAQ Ch. 19 - Prob. 8SAQ Ch. 19 - Prob. 9SAQ Ch. 19 - Prob. 10SAQ

Knowledge Booster

To balance the equation and determining the volume of a 0.500 M K M n O 4 solution required to completely react with 2.85g of Zn.

To balance the equation and determining the volume of a 0.500 M KMnO4 solution required to completely react with 2.85g of Zn.

Want to see the full answer?

Chapter 19 Solutions