Explanation M n O 4 − ( a q ) + Z n ( s ) → M n 2 + ( a q ) + Z n 2 + ( a q ) Step1: Separate the overall reaction into two half-reactions: one for oxidation and one forreduction. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) → M n + 2 ( a q ) Step2: Balance the main elements excluding H, O. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) → M n + 2 ( a q ) Step3: Balance the H, O. For oxidation Z n ( s ) → Z n + 2 ( a q ) For reduction M n O 4 − ( a q ) + 8 H + ( a q ) → M n + 2 ( a q ) + 4 H 2 O ( l ) In these half-reactions, all elements are balanced including H, O. Hence, in the next step we need to balance the charge. Step4: Balance each half-reaction with respect to charge by adding electrons. For oxidation Z n ( s ) → Z n + 2 ( a q ) + 2 e − For reduction M n O 4 − ( a q ) + 8 H + ( a q ) + 5 e − → M n + 2 ( a q ) + 4 H 2 O ( l ) Step5: Make the number of electrons in both half-reactions equal by multiplying one or both half-reactions by a small whole number. For oxidation 5 × [ Z n ( s ) → Z n + 2 ( a q ) + 2 e − ] For reduction 2 × [ M n O 4 − ( a q ) + 8 H + ( a q ) + 5 e − → M n + 2 ( a q ) + 4 H 2 O ( l ) ] By adding these two reactions, we have 2 M n O 4 − ( a q ) + 16 H + ( a q )

Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: A Molecular Approach (4th Edition)

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ISBN: 9780134162485

Author: Nivaldo J. Tro

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Chapter 19, Problem 105E

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To balance the equation and determining the volume of a 0.500 M KMnO4 solution required to completely react with 2.85g of Zn.

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Chapter 19, Problem 104E

Chapter 19, Problem 106E

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Chapter 19 Solutions

Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Chemistry: A Molecular Approach (4th Edition)

Ch. 19 - Prob. 1SAQ Ch. 19 - Q2. Which statement is true for voltaic cells? a)...Ch. 19 - Prob. 3SAQ Ch. 19 - Prob. 4SAQ Ch. 19 - Prob. 5SAQ Ch. 19 - Prob. 6SAQ Ch. 19 - Prob. 7SAQ Ch. 19 - Prob. 8SAQ Ch. 19 - Prob. 9SAQ Ch. 19 - Prob. 10SAQ

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To balance the equation and determining the volume of a 0.500 M K M n O 4 solution required to completely react with 2.85g of Zn.

To balance the equation and determining the volume of a 0.500 M KMnO4 solution required to completely react with 2.85g of Zn.

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Chapter 19 Solutions