Chapter 19, Problem 105CP

Interpretation Introduction

Interpretation:

Interpret the correct nuclear equation from following:

${}_{\text{4}}{\text{Be}}^{\text{7}}\to {}_{\text{3}}{\text{Li}}^{\text{7}}{\text{+}}_{\text{-1}}{\text{e}}^{\text{0}}$

${}_{\text{5}}{\text{B}}^{\text{8}}\to {}_{\text{4}}{\text{Be}}^{\text{8}}{\text{+}}_{\text{1}}{\text{e}}^{\text{0}}$

${}_{\text{94}}{\text{Pu}}^{\text{239}}{\text{+}}_{\text{2}}{\text{He}}^{\text{4}}\to {}_{\text{96}}{\text{Cm}}^{\text{242}}{\text{+}}_{\text{1}}{\text{H}}^{\text{1}}$

${}_{\text{43}}{\text{Tc}}^{\text{97}}{\text{+}}_{\text{-1}}{\text{e}}^{\text{0}}\to {}_{\text{42}}{\text{Mo}}^{\text{97}}$

${}_{\text{4}}{\text{Be}}^{\text{7}}{\text{+}}_{\text{-1}}{\text{e}}^{\text{0}}\to {}_{\text{3}}{\text{Li}}^{\text{7}}$.

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.