Interpret and complete the given table. Initial nuclide Product nuclide Particle produced 9 4 Pu 2 3 9 9 2 U 2 3 5 8 2 Pb 2 1 4 8 3 Bi 2 1 4 2 7 Co 6 0 2 8 Ni 6 0 4 3 Tc 9 9 4 4 Ru 9 9 9 3 Np 2 3 9 9 4 Pu 2 3 9 Concept Introduction: The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay. In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

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Answer 1

Question

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

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a. The change in the Gibbs energy of a certain constant pressure process is found to fit the expression: AG-85.1 J mol −1 +36.5 J mol ¹K-1 × T A. Calculate the value of AS for the process. B. Next, use the Gibbs-Helmholtz equation: (a(AG/T)) ΔΗ - T2 to calculate the value of AH for the process.

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Answer 2

Question

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

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Answer 3

Question

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

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Check out a sample textbook solution

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Answer 4

Question

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

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Answer 5

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

Answer 6

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

Answer 7

Chapter 19, Problem 104CP

Interpretation Introduction

Interpretation:

Interpret and complete the given table.

Initial nuclide Product nuclide Particle produced

₉ ₄ Pu²³⁹ ₉ ₂ U²³⁵

₈ ₂ Pb²¹⁴ ₈ ₃ Bi²¹⁴

₂ ₇ Co⁶⁰ ₂ ₈ Ni⁶⁰

₄ ₃ Tc⁹⁹ ₄ ₄ Ru⁹⁹

₉ ₃ Np²³⁹ ₉ ₄ Pu²³⁹

Concept Introduction:

The decaying of an atom takes place by three type of decay such as alpha decay, beta decay, gama decay.

In alpha decay, an alpha particle with mass 4m and electron 2e removed from nuclide while in beta decay two type of decay are possible beta (+) and beta (-). In gamma decay, nuclide will remain same to the original one.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 19.1 - Prob. 1CT Ch. 19.1 - Prob. 19.1SC Ch. 19.1 - Prob. 19.2SC Ch. 19.3 - Exercise19.3Watches with numerals that glow in the...Ch. 19.8 - Prob. 1CT Ch. 19 - Prob. 1ALQ Ch. 19 - Prob. 2ALQ Ch. 19 - Prob. 3ALQ Ch. 19 - Prob. 4ALQ Ch. 19 - Prob. 5ALQ

Solution Summary: The author explains that the decaying of an atom takes place by three types of decay: alpha, beta, and gama.

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Chapter 19 Solutions

Initial nuclide	Product nuclide	Particle produced
₉ ₄ Pu²³⁹	₉ ₂ U²³⁵
₈ ₂ Pb²¹⁴	₈ ₃ Bi²¹⁴
₂ ₇ Co⁶⁰	₂ ₈ Ni⁶⁰
₄ ₃ Tc⁹⁹	₄ ₄ Ru⁹⁹
₉ ₃ Np²³⁹	₉ ₄ Pu²³⁹