How the UV spectrum of the conjugated product, cholest- 4 -ene- 3 -one is different from that of cholesterol is to be described. Concept introduction: In ultraviolet (UV) spectra of aldehydes and ketones , the strongest absorptions are the ones that results from π to π * electronic transition. In alkenes , these observations are seen at λ max > 200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 1

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Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 2

Question

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 3

Question

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 4

Question

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 5

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

Answer 6

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

Answer 7

Chapter 18.5E, Problem 18.5P

Interpretation Introduction

Interpretation:

How the UV spectrum of the conjugated product, cholest-4-ene-3-one is different from that of cholesterol is to be described.

Concept introduction:

In ultraviolet (UV) spectra of aldehydes and ketones, the strongest absorptions are the ones that results from π to π* electronic transition. In alkenes, these observations are seen at λmax>200 nm only if the carbonyl double bond is in conjugation with another double bond in the molecule.

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Answer 11

Ch. 18.3 - Give the IUPAC name and (if possible) a common...Ch. 18.5D - NMR spectra for two compounds are given here,...Ch. 18.5D - Why were no products from the McLafferty...Ch. 18.5D - Use equations to show the fragmentation leading to...Ch. 18.5E - Prob. 18.5P Ch. 18.7D - Show how you would synthesize each compound from...Ch. 18.8 - Prob. 18.7P Ch. 18.9 - Predict the products of the following reactions....Ch. 18.9 - Show how the following transformations may be...Ch. 18.10 - Prob. 18.10P

Solution Summary: The author explains how the UV spectrum of the conjugated product, cholest- 4 -ene, is different from that of cholesterol.

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