(a) Explanation Given: The function f ( x ) = 3 x − 4 is a probability density function for [ 1 , ∞ ) . Definition used: Median : If X is a continuous random variable with probability function f on [ a , b ] , then the median of X is the number m such that ∫ a m f ( x ) d x = 1 2 . Calculation: Consider the given function f ( x ) = 3 x − 4 for [ 1 , ∞ ) . Use the above mentioned definition and find median, ∫ 1 m 3 x − 4 d x = 1 2 (b) To determine To find: The probability that the random variable is between the expected value and the median.

Finite Mathematics and Calculus with Applications

1st Edition

ISBN: 9781323188361

Author: Margaret Lial

Publisher: Pearson Education

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Chapter 18.2, Problem 20E

(a)

To determine

To compute: The median.

(b)

To determine

To find: The probability that the random variable is between the expected value and the median.

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Chapter 18.2, Problem 19E

Chapter 18.2, Problem 21E

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Chapter 18 Solutions

Finite Mathematics and Calculus with Applications

Ch. 18.1 - Prob. 1YT Ch. 18.1 - Prob. 2YT Ch. 18.1 - Using the probability density function of Example...Ch. 18.1 - Use part (a) of Example 5 to calculate the...Ch. 18.1 - Evaluate each of the following integrals. (Sec....Ch. 18.1 - Prob. 2WE Ch. 18.1 - Prob. 3WE Ch. 18.1 - Decide whether the functions defined as follows...Ch. 18.1 - Prob. 2E Ch. 18.1 - Prob. 3E

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Pulliam found that the time (in...Ch. 18.3 - Life Expectancy According to the National Center...Ch. 18.3 - Prob. 45E Ch. 18.3 - Prob. 46E Ch. 18.3 - Prob. 47E Ch. 18.3 - Prob. 48E Ch. 18.3 - Prob. 49E Ch. 18.3 - Prob. 50E Ch. 18.3 - Prob. 51E Ch. 18.3 - Prob. 52E Ch. 18.3 - Prob. 53E Ch. 18.3 - Prob. 54E Ch. 18 - Prob. 1RE Ch. 18 - Prob. 2RE Ch. 18 - Prob. 3RE Ch. 18 - Prob. 4RE Ch. 18 - Prob. 5RE Ch. 18 - Prob. 6RE Ch. 18 - Prob. 7RE Ch. 18 - Prob. 8RE Ch. 18 - Prob. 9RE Ch. 18 - Prob. 10RE Ch. 18 - Prob. 11RE Ch. 18 - Prob. 12RE Ch. 18 - Prob. 13RE Ch. 18 - Prob. 14RE Ch. 18 - Prob. 15RE Ch. 18 - Prob. 16RE Ch. 18 - Prob. 17RE Ch. 18 - Prob. 18RE Ch. 18 - Prob. 19RE Ch. 18 - Prob. 20RE Ch. 18 - Prob. 21RE Ch. 18 - Prob. 22RE Ch. 18 - Prob. 23RE Ch. 18 - Prob. 24RE Ch. 18 - Prob. 25RE Ch. 18 - Prob. 26RE Ch. 18 - Prob. 27RE Ch. 18 - Prob. 28RE Ch. 18 - Prob. 29RE Ch. 18 - Prob. 30RE Ch. 18 - Prob. 31RE Ch. 18 - Prob. 32RE Ch. 18 - Prob. 33RE Ch. 18 - Prob. 34RE Ch. 18 - Prob. 35RE Ch. 18 - Prob. 36RE Ch. 18 - Prob. 37RE Ch. 18 - Prob. 38RE Ch. 18 - Prob. 39RE Ch. 18 - Prob. 40RE Ch. 18 - Prob. 41RE Ch. 18 - Prob. 42RE Ch. 18 - Prob. 43RE Ch. 18 - Prob. 44RE Ch. 18 - Prob. 45RE Ch. 18 - Prob. 46RE Ch. 18 - Prob. 47RE Ch. 18 - Prob. 48RE Ch. 18 - Prob. 49RE Ch. 18 - Prob. 50RE Ch. 18 - Prob. 51RE Ch. 18 - Prob. 52RE Ch. 18 - Prob. 53RE Ch. 18 - Prob. 54RE Ch. 18 - Prob. 55RE Ch. 18 - Prob. 56RE Ch. 18 - Prob. 57RE Ch. 18 - Prob. 58RE Ch. 18 - Prob. 59RE Ch. 18 - Prob. 60RE Ch. 18 - Prob. 61RE Ch. 18 - Prob. 62RE

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Solution Summary: The author explains that the median is 1.260.