EBK BUSINESS MATH
11th Edition
ISBN: 8220103633802
Author: NOBLE
Publisher: RENT PEARS
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 18.1, Problem 4SE
To determine
To calculate: The total cost of purchase, goods available for sale, total cost of goods available for sale, ending inventory using the specific identification inventory method and to complete the following table,
Date of purchase |
Unitspurchased |
Cost per unit |
Total cost |
Retail price per unit |
Total retail value |
Beginning inventory |
96 |
$12 |
$18 |
||
April 12 |
23 |
$9 |
$13 |
||
May 8 |
15 |
$11 |
$17 |
||
June 2 |
37 |
$15 |
$21 |
||
Goods available for sale |
|||||
Units sold |
89 |
||||
Ending inventory |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The joint pdf of random variables X=1, 2 and Y=1, 2, 3 is
P(X,Y)= X 10.05
Find (a) The value of k.
(c) P(X>1, Y <2).
Y
0.2
0.18
0.15]
(b) the marginal probability function of X and Y.
(d) Ex, Hy
The conditional probability function for the random variables X and Y is
0
P(Y/X) = x0 [0.9
10.1
y
1
2
0.1
0
0.8
0.1
2 0 0.1 0.9.
With P(x=0)=0.2, P(x-1)=0.4. Find P(X,Y), Hx, My, E(XY), OXY.
If X is a continuous random variable
having pdf as shown. Find
1. The constant k.
2. P(X>0).
3. X, X2,0%.
k
p(x)
4
k/2
X
-3
-1
0
1
2
Chapter 18 Solutions
EBK BUSINESS MATH
Ch. 18.1 - Prob. 1-1SCCh. 18.1 - Prob. 1-2SCCh. 18.1 - Prob. 1-3SCCh. 18.1 - Prob. 1-4SCCh. 18.1 - Prob. 2-1SCCh. 18.1 - Prob. 2-2SCCh. 18.1 - Prob. 2-3SCCh. 18.1 - Prob. 2-4SCCh. 18.1 - Prob. 3-1SCCh. 18.1 - Prob. 3-2SC
Ch. 18.1 - Prob. 3-3SCCh. 18.1 - Prob. 3-4SCCh. 18.1 - Prob. 4-1SCCh. 18.1 - Prob. 4-2SCCh. 18.1 - Prob. 4-3SCCh. 18.1 - Prob. 4-4SCCh. 18.1 - Prob. 5-1SCCh. 18.1 - Prob. 5-2SCCh. 18.1 - Prob. 5-3SCCh. 18.1 - Prob. 5-4SCCh. 18.1 - Prob. 6-1SCCh. 18.1 - Prob. 6-2SCCh. 18.1 - Prob. 6-3SCCh. 18.1 - Prob. 6-4SCCh. 18.1 - Prob. 6-5SCCh. 18.1 - Prob. 1SECh. 18.1 - Prob. 2SECh. 18.1 - Prob. 3SECh. 18.1 - Prob. 4SECh. 18.1 - Prob. 5SECh. 18.1 - Prob. 6SECh. 18.1 - Prob. 7SECh. 18.1 - Prob. 8SECh. 18.1 - Prob. 9SECh. 18.1 - Prob. 10SECh. 18.1 - Prob. 11SECh. 18.1 - Prob. 12SECh. 18.1 - Prob. 13SECh. 18.1 - Prob. 14SECh. 18.1 - Prob. 15SECh. 18.1 - Prob. 16SECh. 18.1 - Prob. 17SECh. 18.1 - Prob. 18SECh. 18.1 - Prob. 19SECh. 18.1 - Prob. 20SECh. 18.1 - Prob. 21SECh. 18.1 - Prob. 22SECh. 18.1 - Prob. 23SECh. 18.1 - Prob. 24SECh. 18.1 - Prob. 25SECh. 18.1 - Prob. 26SECh. 18.1 - Prob. 27SECh. 18.1 - Prob. 28SECh. 18.1 - Prob. 29SECh. 18.2 - Prob. 1-1SCCh. 18.2 - Prob. 1-2SCCh. 18.2 - Prob. 1-3SCCh. 18.2 - Prob. 1-4SCCh. 18.2 - Prob. 2-1SCCh. 18.2 - Prob. 2-2SCCh. 18.2 - Prob. 2-3SCCh. 18.2 - Prob. 2-4SCCh. 18.2 - Prob. 1SECh. 18.2 - Prob. 2SECh. 18.2 - Prob. 3SECh. 18.2 - Prob. 4SECh. 18.2 - Prob. 5SECh. 18.2 - Prob. 6SECh. 18.2 - Prob. 7SECh. 18.2 - Prob. 8SECh. 18.2 - Prob. 9SECh. 18.2 - Prob. 10SECh. 18 - Prob. 1ESCh. 18 - Prob. 2ESCh. 18 - Prob. 3ESCh. 18 - Prob. 4ESCh. 18 - Prob. 5ESCh. 18 - Prob. 6ESCh. 18 - Prob. 7ESCh. 18 - Prob. 8ESCh. 18 - Prob. 9ESCh. 18 - Prob. 10ESCh. 18 - Prob. 11ESCh. 18 - Prob. 12ESCh. 18 - Prob. 13ESCh. 18 - Prob. 14ESCh. 18 - Prob. 16ESCh. 18 - Prob. 17ESCh. 18 - Prob. 18ESCh. 18 - Prob. 19ESCh. 18 - Prob. 20ESCh. 18 - Prob. 21ESCh. 18 - Prob. 22ESCh. 18 - Prob. 23ESCh. 18 - Prob. 24ESCh. 18 - Prob. 25ESCh. 18 - Prob. 26ESCh. 18 - Prob. 27ESCh. 18 - Prob. 1PTCh. 18 - Prob. 2PTCh. 18 - Prob. 3PTCh. 18 - Prob. 4PTCh. 18 - Prob. 5PTCh. 18 - Prob. 6PTCh. 18 - Prob. 7PTCh. 18 - Prob. 8PTCh. 18 - Prob. 9PTCh. 18 - Prob. 10PTCh. 18 - Prob. 11PTCh. 18 - Prob. 12PTCh. 18 - Prob. 13PTCh. 18 - Prob. 14PTCh. 18 - Prob. 15PTCh. 18 - Prob. 16PTCh. 18 - Prob. 1CTCh. 18 - Prob. 2CTCh. 18 - Prob. 3CTCh. 18 - Prob. 4CTCh. 18 - Prob. 5CTCh. 18 - Prob. 6CTCh. 18 - Prob. 7CTCh. 18 - Prob. 8CTCh. 18 - Prob. 9CTCh. 18 - Prob. 1CPCh. 18 - Prob. 2CPCh. 18 - Prob. 1CS1Ch. 18 - Prob. 2CS1Ch. 18 - Prob. 3CS1Ch. 18 - Prob. 1CS2Ch. 18 - Prob. 2CS2
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.Similar questions
- Given a normally distributed variable X with mean 10 and standard deviation 4, find: 1. P(X5).arrow_forwardCalculus lll May I please have an explanation about how to calculate the derivative of the surface (the dS) on the surface integral, and then explain the essentials of the surface integral?arrow_forwardFor the Big-M tableau (of a maximization LP and row0 at bottom and M=1000), Z Ꮖ 1 x2 x3 81 82 83 e4 a4 RHS 0 7 0 0 1 0 4 3 -3 20 0 -4.5 0 0 0 1 -8 -2.5 2.5 6 0 7 0 1 0 0 8 3 -3 4 0 -1 50 1 0 0 0-2 -1 1 4 0000 0 30 970 200 If the original value of c₁ is increased by 60, what is the updated value of c₁ (meaning keeping the same set for BV. -10? Having made that change, what is the new optimal value for ž?arrow_forward
- 32. Consider a normally distributed population with mean μ = 80 and standard deviation σ = 14. a. Construct the centerline and the upper and lower control limits for the chart if samples of size 5 are used. b. Repeat the analysis with samples of size 10. 2080 101 c. Discuss the effect of the sample size on the control limits.arrow_forwardConsider the following hypothesis test. The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n 1 = 80 n 2 = 70 x 1 = 104 x 2 = 106 σ 1 = 8.4 σ 2 = 7.6 What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals). What is the p-value (to 4 decimals)? Use z-table. With = .05, what is your hypothesis testing conclusion?arrow_forwardPeriodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B = 16 = 10 = 6.82 = 6.25 = .64 = .75 State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2 Compute the value of the test statistic (to 2 decimals). What is the p-value?The p-value is What is your conclusion?arrow_forward
- A firm paid its first annual dividend yesterday in the amount of $.15 per share. The company plans to double the dividend in each of the next 3 years. Starting in Year 4, the firm plans to pay $1.50 per share indefinitely. What is one share of this stock worth today if the market rate of return on similar securities is 13.8 percent? Multiple Choice $11.79 $8.92 $10.77 $11.02 $10.26arrow_forwardУ1 = e is a solution to the differential equation xy" — (x+1)y' + y = 0. Use reduction of order to find the solution y(x) corresponding to the initial data y(1) = 1, y′ (1) = 0. Then sin(y(2.89)) is -0.381 0.270 -0.401 0.456 0.952 0.981 -0.152 0.942arrow_forwardHere is the optimal tableau for a standard Max problem. zx1 x2 x3 24 81 82 83 rhs 1 0 5 3 0 6 0 1 .3 7.5 0 - .1 .2 0 0 28 360 0 -8 522 0 2700 0 6 12 1 60 0 0 -1/15-3 1 1/15 -1/10 0 2 Using that the dual solution y = CBy B-1 and finding B = (B-¹)-¹ we find the original CBV and rhs b. The allowable increase for b₂ is If b₂ is increased by 3 then, using Dual Theorem, the new value for * is If c₂ is increased by 10, then the new value for optimal > is i.e. if no change to BV, then just a change to profit on selling product 2. The original coefficients c₁ = =☐ a and c4 = 5 If c4 is changed to 512, then (first adjusting other columns of row0 by adding Delta times row belonging to x4 or using B-matrix method to update row0) the new optimal value, after doing more simplex algorithm, for > isarrow_forward
- 10 6 9. 8 -7- 6. 5. 4- 3. 2 1- -1 0 -1 2 3 4 ·10 5 6 7 00 8 6 10arrow_forwardsolve pleasearrow_forwardWeek 3: Mortgages and Amortiza X + rses/167748/assignments/5379530?module_item_id=23896312 11:59pm Points 10 Submitting an external tool Gider the following monthly amortization schedule: Payment # Payment Interest Debt Payment Balance 1 1,167.34 540.54 626.80 259,873.20 2 1,167.34 539.24 628.10 259,245.10 3 1,167.34 With the exception of column one, all amounts are in dollars. Calculate the annual interest rate on this loa Round your answer to the nearest hundredth of a percent. Do NOT round until you calculate the final answer. * Previous a Earrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Discrete Mathematics and Its Applications ( 8th I...MathISBN:9781259676512Author:Kenneth H RosenPublisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...MathISBN:9780134392790Author:Beckmann, SybillaPublisher:PEARSON
Thinking Mathematically (7th Edition)MathISBN:9780134683713Author:Robert F. BlitzerPublisher:PEARSON
Discrete Mathematics With ApplicationsMathISBN:9781337694193Author:EPP, Susanna S.Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)MathISBN:9781259985607Author:David Sobecki Professor, Brian A. MercerPublisher:McGraw-Hill Education
Discrete Mathematics and Its Applications ( 8th I...
Math
ISBN:9781259676512
Author:Kenneth H Rosen
Publisher:McGraw-Hill Education
Mathematics for Elementary Teachers with Activiti...
Math
ISBN:9780134392790
Author:Beckmann, Sybilla
Publisher:PEARSON
Thinking Mathematically (7th Edition)
Math
ISBN:9780134683713
Author:Robert F. Blitzer
Publisher:PEARSON
Discrete Mathematics With Applications
Math
ISBN:9781337694193
Author:EPP, Susanna S.
Publisher:Cengage Learning,
Pathways To Math Literacy (looseleaf)
Math
ISBN:9781259985607
Author:David Sobecki Professor, Brian A. Mercer
Publisher:McGraw-Hill Education
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY