Building Java Programs: A Back to Basics Approach (4th Edition)
4th Edition
ISBN: 9780134322766
Author: Stuart Reges, Marty Stepp
Publisher: PEARSON
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Chapter 18.1, Problem 1SCP
Explanation of Solution
Hashing:
- In the concept of hashing, a hash function is used to map the keys to some values.
- In some cases, these hashing functions may lead to collision which means two or more keys are mapped to same value.
- Such collisions are avoided with the use of chain hashing.
- In case of chain hashing, each cell of hash table points to a linked list of records that have same hash function value...
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7. Long-Distance CallsA long-distance provider charges the following rates for telephone calls:
Rate Category Rate per MinuteDaytime (6:00 a.m. through 5:59 p.m.) $0.07Evening (6:00 p.m. through 11:59 p.m.) $0.12Off-Peak (midnight through 5:59 a.m.) $0.05Write a GUI application that allows the user to select a rate category (from a set of radio buttons), and enter the number of minutes of the call into an Entry widget. An info dialog box should display the charge for the call.
Name and Address
The Name and Address Problem
Write a GUI program that displays your name and address when a button is clicked. The program’s window should appear as the sketch on the left side of Figure 13-61 when it runs. When the user clicks the Show Info button, the program should display your name and address, as shown in the sketch on the right of the figure.
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 18 Solutions
Building Java Programs: A Back to Basics Approach (4th Edition)
Ch. 18.1 - Prob. 1SCPCh. 18.1 - Prob. 2SCPCh. 18.1 - Prob. 3SCPCh. 18.1 - Prob. 4SCPCh. 18.1 - Prob. 5SCPCh. 18.1 - Prob. 6SCPCh. 18.1 - Prob. 7SCPCh. 18.1 - Prob. 8SCPCh. 18.1 - Prob. 9SCPCh. 18.1 - Prob. 10SCP
Ch. 18.1 - Prob. 11SCPCh. 18.1 - Prob. 12SCPCh. 18.2 - Prob. 13SCPCh. 18.2 - Prob. 14SCPCh. 18.2 - Prob. 15SCPCh. 18.2 - Prob. 17SCPCh. 18.2 - Prob. 18SCPCh. 18.2 - Prob. 19SCPCh. 18.2 - Prob. 20SCPCh. 18.2 - Prob. 21SCPCh. 18.2 - Prob. 22SCPCh. 18.2 - Prob. 23SCPCh. 18.2 - Prob. 24SCPCh. 18.2 - Prob. 25SCPCh. 18.2 - Prob. 26SCPCh. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9E
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