Explanation Formula Used: Green’s Theorem – I = ∮ C F ⋅ d r = ∬ D ( ∂ Q ∂ x − ∂ P ∂ y ) d A Given: F ( x , y ) = 〈 x 3 , 4 x 〉 Calculation: To compute integral of the given path we have to compute the area of the closed region shown in figure below using Green’s theorem, Using Green’s theorem and line integrals, we can say, I = ∮ C F ⋅ d r = ∬ D ( ∂ Q ∂ x − ∂ P ∂ y ) d A = ∫ C F ( x , y ) d r + ∫ B A ¯ F ( x , y ) d r ----------------------(1) Now let’s first find line integral along B A ¯ Therefore, we have to parameterize F ( x , y ) = 〈 x 3 , 4 x 〉 along B A ¯ x = − 1 and y = t − 1 ≤ t ≤ 0 Therefore, d x d t = 0 and d y d t = 1 Line integral of F along B A ¯ is given by, ∫ B A ¯ F ( x , y ) d r Now, F ( x , y ) = 〈 x 3 , 4 x 〉 = 〈 ( − 1 ) 3 , 4 ( − 1 ) 〉 = 〈 − 1 , − 4 〉 d r = 〈 d x d t , d y d t 〉 d t = 〈 0 , 1 〉 d t Therefore, ∫ B A ¯ F ( x , y ) d r = ∫ − 1 0 〈 − 1 , − 4 〉 ⋅ 〈 0 , 1 〉 d t ∫ B A ¯ F ( x , y ) d r = ∫ − 1 0 ( − 1 ) ( 0 ) + ( − 4 ) ( 1 ) d t ∫ B A ¯ F ( x , y ) d r = ∫ − 1 0 − 4 d t = − 4 ∫ − 1 0 d t ∫ B A ¯ F ( x , y ) d r = − 4 [ t ] − 1 0 = − 4 ( 0 − ( − 1 ) ) ∫ B A ¯ F ( x , y ) d r = − 4 --------------------------------(2) Now, using Green’s theorem let’s find area of the closed region D...

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 18.1, Problem 14E

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To compute: integral of $F (x, y) = 〈 x^{3}, 4 x 〉$

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Chapter 18.1, Problem 13E

Chapter 18.1, Problem 15E

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Chapter 18 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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integral of F ( x , y ) = 〈 x 3 , 4 x 〉

Solution Summary: The author explains how to compute the integral of the given path using Green’s theorem and line integrals.

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To compute: integral of $F (x, y) = 〈 x^{3}, 4 x 〉$

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Chapter 18 Solutions

integral of F ( x , y ) = 〈 x 3 , 4 x 〉

Solution Summary: The author explains how to compute the integral of the given path using Green’s theorem and line integrals.

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To compute: integral of F(x,y)=〈x3,4x〉

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Chapter 18 Solutions

To compute: integral of $F (x, y) = 〈 x^{3}, 4 x 〉$