Explanation The expression of root mean square velocity of gas is 3 R T M . The expression of initial root mean square velocity of gas is, ( V rms ) 1 = 3 R T 1 M ( V rms ) 1 ∝ T 1 (I) ( V rms ) 1 is the initial root mean square velocity of gas. R is the gas constant. T 1 is the initial temperature of the gas. M is the molecular mass of the gas. The expression of final root mean square velocity of gas is, ( V rms ) 2 = 3 R T 2 M ( V rms ) 2 ∝ T 2 (II) ( V rms ) 2 is the final root mean square velocity of gas. T 2 is the final temperature of the gas. When the final velocity of the gas is twice of the initial velocity, ( V rms ) 2 = 2 ( V rms ) 1 From equation (I) and (II)

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Chapter 18, Problem Q18.21DQ

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The factor by which the Kelvin temperature of the gas be increased.

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Chapter 18, Problem Q18.20DQ

Chapter 18, Problem Q18.22DQ

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Chapter 18 Solutions

University Physics, Volume 2 - Technology Update Custom Edition for Texas A&M - College Station, 2/e

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The factor by which the Kelvin temperature of the gas be increased.

Solution Summary: The author explains that the expression of root mean square velocity of gas is sqrt3RTM.

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The factor by which the Kelvin temperature of the gas be increased.

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Chapter 18 Solutions