The equilibrium constant for the formation of NiO at 1627 ° C should be calcualted under given conditions. Concept introduction: The Gibbs free energy or the free energy change is a thermodynamic quantity represented by Δ r G o . It can be calculated in a similar manner as entropy and enthalpy. The expression for the free energy change is: Δ r G ° = ∑ nΔ f G ° ( products ) - ∑ nΔ f G ° ( reactants ) Δ f G o is related to the equilibrium constant K by the equation, Δ f G o = -RTlnK p The rearranged expression is, K p = e - Δ f G o RT Δ f G o is also related to the reaction quotient Q by the expression, Δ f G = Δ f G ° +RTlnQ For a general reaction, aA + bB → cC + dD Q = [ C ] c [ D ] d [ A ] a [ B ] b
The equilibrium constant for the formation of NiO at 1627 ° C should be calcualted under given conditions. Concept introduction: The Gibbs free energy or the free energy change is a thermodynamic quantity represented by Δ r G o . It can be calculated in a similar manner as entropy and enthalpy. The expression for the free energy change is: Δ r G ° = ∑ nΔ f G ° ( products ) - ∑ nΔ f G ° ( reactants ) Δ f G o is related to the equilibrium constant K by the equation, Δ f G o = -RTlnK p The rearranged expression is, K p = e - Δ f G o RT Δ f G o is also related to the reaction quotient Q by the expression, Δ f G = Δ f G ° +RTlnQ For a general reaction, aA + bB → cC + dD Q = [ C ] c [ D ] d [ A ] a [ B ] b
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 18, Problem 82IL
Interpretation Introduction
Interpretation:
The equilibrium constant for the formation of NiO at 1627 °C should be calcualted under given conditions.
Concept introduction:
The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔrGo. It can be calculated in a similar manner as entropy and enthalpy. The expression for the free energy change is:
ΔrG°= ∑nΔfG°(products)- ∑nΔfG°(reactants)
ΔfGo is related to the equilibrium constant K by the equation,
ΔfGo= -RTlnKp
The rearranged expression is,
Kp= e-ΔfGoRT
ΔfGo is also related to the reaction quotient Q by the expression,
9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer
appropriately in the box. Only the answer in the box will be graded. (3) points)
OH
OH
بر بد بدید
2
3
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
Chapter 18 Solutions
OWLv2 6-Months Printed Access Card for Kotz/Treichel/Townsend's Chemistry & Chemical Reactivity, 9th, 9th Edition
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY