An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni 2+ ] = 1.0 M separated by a porous disk from an aluminum metal electrode immersed in a solution with [Al 3+ ] = 1.0 M. Sodium hydroxide is added to the aluminum compartment, causing Al(OH) 3 ( s ) to precipitate. After precipitation of Al(OH) 3 has ceased, the concentration of OH − is 1.0 × 10 −4 M and the measured cell potential is 1.82 V. Calculate the K sp value for Al(OH) 3 . Al(OH) 3 ( s ) ⇌ Al 3+ ( a q ) + 3OH − ( a q ) K sp = ?
An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni 2+ ] = 1.0 M separated by a porous disk from an aluminum metal electrode immersed in a solution with [Al 3+ ] = 1.0 M. Sodium hydroxide is added to the aluminum compartment, causing Al(OH) 3 ( s ) to precipitate. After precipitation of Al(OH) 3 has ceased, the concentration of OH − is 1.0 × 10 −4 M and the measured cell potential is 1.82 V. Calculate the K sp value for Al(OH) 3 . Al(OH) 3 ( s ) ⇌ Al 3+ ( a q ) + 3OH − ( a q ) K sp = ?
Solution Summary: The author explains how the value of K_sp is calculated using Nernst formula, E=E°-(RTnFright
An electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] = 1.0 M separated by a porous disk from an aluminum metal electrode immersed in a solution with [Al3+] = 1.0 M. Sodium hydroxide is added to the aluminum compartment, causing Al(OH)3(s) to precipitate. After precipitation of Al(OH)3 has ceased, the concentration of OH− is 1.0 × 10−4M and the measured cell potential is 1.82 V. Calculate the Ksp value for Al(OH)3.
Al(OH)
3
(
s
)
⇌
Al
3+
(
a
q
)
+
3OH
−
(
a
q
)
K
sp
=
?
Definition Definition Study of chemical reactions that result in the production of electrical energy. Electrochemistry focuses particularly on how chemical energy is converted into electrical energy and vice-versa. This energy is used in various kinds of cells, batteries, and appliances. Most electrochemical reactions involve oxidation and reduction.
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment?
a) the heat capacity of the calorimeter
b) Mass of sample
c) Ti
d) The molarity of the HCl
e) Tf
Predict products for the Following organic rxn/s by
writing the structurels of the correct products. Write
above the line provided"
your answer
D2
①CH3(CH2) 5 CH3 + D₂ (adequate)"
+
2
mited)
19
Spark
Spark
por every item.
4 CH 3 11
3 CH 3 (CH2) 4 C-H + CH3OH
CH2 CH3 + CH3 CH2OH
0
CH3
fou
+
KMnDy→
C43
+ 2 KMn Dy→→
C-OH
")
0
C-OH
1110
(4.)
9+3
=C
CH3
+ HNO 3
0
+ Heat>
+ CH3 C-OH + Heat
CH2CH3
- 3
2
+ D Heat H
3
CH 3 CH₂ CH₂ C = CH + 2 H₂ →
2
2
Chapter 18 Solutions
WebAssign for Zumdahl/Zumdahl/DeCoste's Chemistry, 10th Edition [Instant Access], Single-Term
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell