(b) To determine: ∆ G rxn for the following reaction at 25 o C at equilibrium. C O ( g ) + C C l 4 ( g ) ⇌ 2 C O C l 2 ( g ) K P = 2.26 × 10 4 at 25 0 C

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Answer 1

Question

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

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Heating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of S№1. 2nd attempt 0 See Periodic Table See Hint Draw the organic intermediate from the first step (no byproducts) and draw curved arrow(s) to show how it reacts. TH +11: 1st attempt Feedback H H H C F F See Periodic Table See Hint

Answer 2

Question

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

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Answer 3

Question

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

Expert Solution & Answer

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Answer 5

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

Answer 6

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Answer 7

Chapter 18, Problem 75E

Interpretation Introduction

(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

Answer 8

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

Answer 9

Interpretation Introduction

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

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(b) To determine: ∆ G rxn for the following reaction at 25 o C at equilibrium. C O ( g ) + C C l 4 ( g ) ⇌ 2 C O C l 2 ( g ) K P = 2.26 × 10 4 at 25 0 C

Solution Summary: The author calculates G rxn for the reaction at 25 o C for standard condition, at equilibrium and for P C H 3 O H = 1.0 atm.

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(b)

To determine:

$∆ G_{rxn}$ for the following reaction at 25^oC at equilibrium.

$\begin{array}{l} C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)} \\ K_{P} = 2.26 \times 10^{4} {at 25}^{0} C \end{array}$

(c)

To determine:

$∆ G_{rxn}$ for the following reaction at 25⁰C for $P_{C H_{3} O H} = 1.0 {atm; P}_{C O} = P_{H_{2}} = 0.010 atm$

For the reaction: $C O_{(g)} + C C l_{4}_{(g)} ⇌ 2 C O C l_{2}_{(g)}$

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Chapter 18 Solutions

(b) To determine: ∆ G rxn for the following reaction at 25 o C at equilibrium. C O ( g ) + C C l 4 ( g ) ⇌ 2 C O C l 2 ( g ) K P = 2.26 × 10 4 at 25 0 C

Solution Summary: The author calculates G rxn for the reaction at 25 o C for standard condition, at equilibrium and for P C H 3 O H = 1.0 atm.

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