1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not. 2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge. 3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons. Concept introduction: The conditions for aromatic compound are, 1. It should be planar 2. It must obey the Huckel’s rule The requirement of an odd number of electron pair is called Huckel’s rule . A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic. 3. Continuous conjugated π system(all carbon should be in sp 2 hybridized state)

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Answer 1

Question

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

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Answer 2

Question

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

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Answer 3

Question

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

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Answer 4

Question

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

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Answer 5

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

Answer 6

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

Answer 7

Chapter 18, Problem 67IP

Interpretation Introduction

Interpretation:

1) For the given compounds A and B, it should be checked whether the 14- membered ring in the compound B are aromatic or not.

2) Resonance structure of the compound B should be drawn by showing the delocalization of negative charge.

3) Resonance structure of the compound B should be drawn by showing the delocalization of unpaired electrons.

Concept introduction:

The conditions for aromatic compound are,

1. It should be planar

2. It must obey the Huckel’s rule

The requirement of an odd number of electron pair is called Huckel’s rule. A compound can only be aromatic if the number of π electron in the ring is 2, 6,10,14,18 and so on. This series of number can be expressed mathematically as 4n+2 , where n should be an integer and the compound is aromatic.

3. Continuous conjugated π system(all carbon should be in sp2 hybridized state)

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 18.2 - Prob. 1LTS Ch. 18.2 - Prob. 1PTS Ch. 18.2 - Prob. 2ATS Ch. 18.2 - Prob. 3ATS Ch. 18.2 - Prob. 4ATS Ch. 18.2 - Prob. 5ATS Ch. 18.4 - Prob. 6CC Ch. 18.4 - Prob. 8CC Ch. 18.4 - Prob. 9CC Ch. 18.5 - Prob. 10CC

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Chapter 18 Solutions