Explanation Given data: Radius of the glass cylinder is R . Height of ray from the principal axis is R 2 . Explanation: Modify FIGURE P18.66 as shown in Figure 1. Write the expression of sin θ incident for a right angled triangle by using trigonometric rule. sin θ incident = R 2 R = R 2 ( R ) = 1 2 θ incident = sin − 1 ( 1 2 ) = 30 ° By using Snell’s law, n incident n glass = sin θ glass sin θ incident sin θ incident sin θ glass = n glass n iincident sin θ glass = n incident n glass × sin θ incident θ glass = sin − 1 ( n incident n glass × sin θ incident ) Here, n glass is the refractive index of glass, which has standard value as 1

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+)

4th Edition

ISBN: 9780137561520

Author: Randall Knight, Brian Jones

Publisher: PEARSON+

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Question

Chapter 18, Problem 66GP

To determine

The angle α for the ray after it has entered the cylinder.

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Chapter 18, Problem 65GP

Chapter 18, Problem 67GP

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Chapter 18 Solutions

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+)

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