Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
Question
Book Icon
Chapter 18, Problem 55P
Interpretation Introduction

(a)

Interpretation: The carbonyl compound and amine or alcohol needed to prepare the given compound are to be predicted.

Concept introduction: A carbonyl compound (aldehyde or ketone) reacts with 1ο amine to yield imine, and reacts with 2ο amine to yield enamine. The mechanism of both reactions are identical except for the last step. The last step for enamine formation involves loss of a proton from the adjacent CH bond, whereas the last step for imine formation involves loss of a proton from the N atom itself.

Interpretation Introduction

(b)

Interpretation: The carbonyl compound and amine or alcohol needed to prepare the given compound are to be predicted.

Concept introduction: A carbonyl compound (aldehyde or ketone) reacts with 1ο amine to yield imine, and reacts with 2ο amine to yield enamine. The mechanism of both reactions are identical except for the last step. The last step for enamine formation involves loss of a proton from the adjacent CH bond, whereas the last step for imine formation involves loss of a proton from the N atom itself.

Interpretation Introduction

(c)

Interpretation: The carbonyl compound and amine or alcohol needed to prepare the given compound are to be predicted.

Concept introduction: Acetals are the groups in which carbon atom is bonded with two OR groups through single bonds. A carbonyl compound (aldehyde or ketone) yields an acetal, when it is treated with two equivalents of an alcohol or one equivalent of diol in the presence of strong acid. The reaction is reversible.

Interpretation Introduction

(d)

Interpretation: The carbonyl compound and amine or alcohol needed to prepare the given compound are to be predicted.

Concept introduction: Acetals are the groups in which carbon atom is bonded with two OR groups through single bonds. A carbonyl compound (aldehyde or ketone) yields an acetal, when it is treated with two equivalents of an alcohol or one equivalent of diol in the presence of strong acid. The reaction is reversible.

Blurred answer
Students have asked these similar questions
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.   Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment? a) the heat capacity of the calorimeter b) Mass of sample c) Ti d) The molarity of the HCl e) Tf
Predict products for the Following organic rxn/s by writing the structurels of the correct products. Write above the line provided" your answer D2 ①CH3(CH2) 5 CH3 + D₂ (adequate)" + 2 mited) 19 Spark Spark por every item. 4 CH 3 11 3 CH 3 (CH2) 4 C-H + CH3OH CH2 CH3 + CH3 CH2OH 0 CH3 fou + KMnDy→ C43 + 2 KMn Dy→→ C-OH ") 0 C-OH 1110 (4.) 9+3 =C CH3 + HNO 3 0 + Heat> + CH3 C-OH + Heat CH2CH3 - 3 2 + D Heat H 3 CH 3 CH₂ CH₂ C = CH + 2 H₂ → 2 2

Chapter 18 Solutions

Organic Chemistry (6th Edition)

Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning