Explanation Given data: Radius of the glass cylinder is R . Height of ray from the principal axis is R 2 . Modify FIGURE P18.50 as shown in Figure 1. Write the expression of sin θ incident for a right angled triangle by using trigonometric rule. sin θ incident = R 2 R = R 2 ( R ) = 1 2 θ incident = sin − 1 ( 1 2 ) = 30 ° By using Snell’s law, n incident n glass = sin θ glass sin θ incident sin θ incident sin θ glass = n glass n iincident sin θ glass = n incident n glass × sin θ incident θ glass = sin − 1 ( n incident n glass × sin θ incident ) Here, n glass is the refractive index of glass, which has standard value as 1

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321908803

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 18, Problem 50GP

To determine

The angle α for the ray after it has entered the cylinder.

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Chapter 18, Problem 49GP

Chapter 18, Problem 51GP

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Chapter 18 Solutions

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

Ch. 18 - Prob. 1CQ Ch. 18 - Prob. 2CQ Ch. 18 - Can you see the rays from the sun on a clear day?...Ch. 18 - If you take a walk on a summer night along a dark,...Ch. 18 - You are looking at the image of a pencil in a...Ch. 18 - Prob. 6CQ Ch. 18 - In Manets A Bar at the Folies-Bergere (see Figure...Ch. 18 - Explain why ambulances have the word AMBULANCE...Ch. 18 - a. Consider one point on an object near a lens....Ch. 18 - When you look at your reflection in the bowl of a...

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The angle α for the ray after it has entered the cylinder.

Solution Summary: The author explains how to determine the angle of the ray after it enters the glass cylinder by using Snell's law.

The angle α for the ray after it has entered the cylinder.

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Chapter 18 Solutions