
Concept explainers
Explanation of Solution
Given code:
//implement the "List" interface
List <String> nameList = new ArrayList<>(); //Line 1
//declare the "ListIterator"
ListIterator it = new ListIterator(nameList); //Line 2
//set the value
it.set("Herbert"); //Line 3
Errors in the given code:
Error #1:
The error is in “Line 2”. For obtaining the list iterator for the variable “nameList”, the user need to call its list iterator method.
Correct statement:
//declare the "ListIterator"
ListIterator <String> it = nameList.ListIterator();
Error #2:
The “set” method can only be called after a successful call to one of the method “next()” or “previous()”.
Corrected statement:
//check the condition
if (it.hasNext())
{
//get the first element
it.next();
//set the value
it...

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Chapter 18 Solutions
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