Chapter 18, Problem 43AE

(a)

Interpretation Introduction

Interpretation:

 The balanced beta emission ${}_{12}^{29}\text{Mg}$ has to be written.

Concept Introduction:

Beta-emission involves liberation of a beta-particle that is represented as ${}_{-1}^0\text{e}$. The general equation for beta emission process is written as follows:

  ${}_{\text{Z}}^{\text{A}}\text{Y}{\to }_{\text{Z+1}}^{\text{A}}\text{X}{+}_{-1}^0\text{e}$

Here,

Mass number is denoted by A.

Atomic number denoted by Z.

The initial nuclide is denoted as Y.

The product nuclide is Y.

(b)

Interpretation Introduction

Interpretation:

 The balanced alpha emission ${}_{60}^{150}\text{Nd}$ has to be written.

Concept Introduction:

Alpha-emission involves liberation of a ${}_2^4\text{He}$. The general equation for alpha emission process is written as follows:

  ${}_{\text{Z}}^{\text{A}}\text{Y}{\to }_{Z-2}^{\text{A}}\text{X}{+}_2^4\text{He}$

Here,

Mass number is denoted by A.

Atomic number denoted by Z.

The initial nuclide is denoted as Y.

The product nuclide is Y.

(c)

Interpretation Introduction

Interpretation:

 The balanced positron emission ${}_{33}^{72}\text{As}$ has to be written.

Concept Introduction:

Positron -emission involves liberation of positron that is represented as ${}_{+1}^0\text{e}$. The general equation positron emission process is written as follows:

  ${}_{\text{Z}}^{\text{A}}\text{Y}{\to }_{\text{Z}-\text{1}}^{\text{A}}\text{X}{+}_{+1}^0\text{e}$

Here,

Mass number is denoted by A.

Atomic number denoted by Z.

The initial nuclide is denoted as Y.

The product nuclide is Y.