ORGANIC CHEM. - ACCESS PKG+MODELING KIT
4th Edition
ISBN: 9781119838746
Author: Klein
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 18, Problem 38PP
Interpretation Introduction
Interpretation: The given following transformations should be determined.
Concept Introduction:
Electrophile: It is positively charged species which seeks for negative charge and hence accepts pair of electrons from negatively charged species (Nucleophiles) which results in the formation of
Electrophilic substitution reactions are
Expert Solution & Answer
Answer to Problem 38PP
Explanation of Solution
Chlorination of benzene.
Benzene reacts with Chlorine in an electrophilic substitution reaction, other than only in the presence of a catalyst. These compounds act as the catalyst and perform precisely like Aluminium chloride in these reactions.
Bromination of benzene.
Explanation: Benzene reacts with Bromine in an electrophilic substitution reaction, other than only in the presence of a catalyst. These compounds act as the catalyst and perform precisely like Aluminium bromide in these reactions.
Nitration followed by nitro reduction.
Nitration is a universal group of chemical procedure for the opening of a nitro group keen on an organic chemical compound. Extra loosely the term as well is applied imperfectly to the different process of forming nitrate esters between alcohols and nitric acid. Nitro group is converted into
Sulfonation of benzene.
Sulfonation is a reversible reaction so as to produces Benzene sulfonic acid by adding fuming Sulfuric acid.
Friedel-Crafts acyation followed by Clemmensen reduction.
Friedel-Crafts acyation of benzene linking an electrophilic substitution reaction between benzene and alkyl chloride in the presence of an Aluminium chloride catalyst.
Clemmensen reduction is a chemical reaction explain because a reduction of
Friedel Crafts alkylation followed by Oxidation.
Friedel Crafts alkylation involves the alkylation of an
Conclusion
The given following transformations should be determined.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Draw one product of an elimination reaction between the molecules below.
Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction
'O
10
+
x
也
HO
+
义
Click and drag to start
drawing a structure.
What are the angles a and b in the actual molecule of which this is a Lewis structure?
H-
:0:
C=N:
b
Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron
groups may have slightly different sizes.
a = 0°
b=0
X
A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but
there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing
from the arrow.
• Is the student's transformation possible? If not, check the box under the drawing area.
• If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required
catalysts, inorganic reagents, or other important reaction conditions above and below the arrow.
• You do not need to balance the reaction, but be sure every important organic reactant or product is shown.
+
This transformation can't be done in one step.
T
i
Chapter 18 Solutions
ORGANIC CHEM. - ACCESS PKG+MODELING KIT
Ch. 18.2 - Prob. 1CCCh. 18.3 - Prob. 2CCCh. 18.3 - Prob. 3CCCh. 18.4 - Prob. 4CCCh. 18.5 - Prob. 5CCCh. 18.5 - Prob. 6CCCh. 18.5 - Prob. 7CCCh. 18.6 - Prob. 8CCCh. 18.6 - Prob. 9CCCh. 18.6 - Prob. 10CC
Ch. 18.7 - Prob. 11CCCh. 18.7 - Prob. 12CCCh. 18.8 - Prob. 13CCCh. 18.9 - Prob. 14CCCh. 18.9 - Prob. 15CCCh. 18.10 - Prob. 1LTSCh. 18.10 - Prob. 16PTSCh. 18.10 - Prob. 17ATSCh. 18.11 - Prob. 2LTSCh. 18.11 - Prob. 18PTSCh. 18.12 - Prob. 24CCCh. 18.12 - Prob. 25CCCh. 18.12 - Prob. 5LTSCh. 18.12 - Prob. 26PTSCh. 18.12 - Prob. 6LTSCh. 18.12 - Prob. 28PTSCh. 18.13 - Prob. 30CCCh. 18.13 - Prob. 31CCCh. 18.13 - Prob. 32CCCh. 18.14 - Prob. 33CCCh. 18.14 - Prob. 34CCCh. 18.15 - Prob. 7LTSCh. 18.15 - Prob. 35PTSCh. 18.15 - Prob. 36PTSCh. 18 - Prob. 38PPCh. 18 - Prob. 39PPCh. 18 - Prob. 40PPCh. 18 - Prob. 41PPCh. 18 - Prob. 42PPCh. 18 - Prob. 43PPCh. 18 - Prob. 45PPCh. 18 - Prob. 46PPCh. 18 - Prob. 47PPCh. 18 - Prob. 48PPCh. 18 - Prob. 49PPCh. 18 - Prob. 50PPCh. 18 - Prob. 51PPCh. 18 - Prob. 52PPCh. 18 - Prob. 53PPCh. 18 - Prob. 54PPCh. 18 - Prob. 55PPCh. 18 - Prob. 56PPCh. 18 - Prob. 57PPCh. 18 - Prob. 58PPCh. 18 - Prob. 59PPCh. 18 - Prob. 60PPCh. 18 - Prob. 61PPCh. 18 - Prob. 62PPCh. 18 - Prob. 63PPCh. 18 - Prob. 64PPCh. 18 - Prob. 80IPCh. 18 - Prob. 81IPCh. 18 - Prob. 82IPCh. 18 - Prob. 83IPCh. 18 - Prob. 84IPCh. 18 - Prob. 85IPCh. 18 - Prob. 86IPCh. 18 - Prob. 87IPCh. 18 - Prob. 88IPCh. 18 - Prob. 89IP
Knowledge Booster
Similar questions
- Determine the structures of the missing organic molecules in the following reaction: H+ O OH H+ + H₂O ☑ ☑ Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structure of the missing organic molecule X. Molecule X shows up in multiple steps, but you only have to draw its structure once. Click and drag to start drawing a structure. X § ©arrow_forwardTable 1.1 Stock Standard Solutions Preparation. The amounts shown should be dissolved in 100 mL. Millipore water. Calculate the corresponding anion concentrations based on the actual weights of the reagents. Anion Amount of reagent (g) Anion Concentration (mg/L) 0.1649 Reagent Chloride NaCl Fluoride NaF 0.2210 Bromide NaBr 0.1288 Nitrate NaNO3 0.1371 Nitrite NaNO2 0.1500 Phosphate KH2PO4 0.1433 Sulfate K2SO4 0.1814arrow_forwardDraw the structure of the pound in the provided CO as a 300-1200 37(2), 11 ( 110, and 2.5 (20arrow_forward
- Please help me with # 4 and 5. Thanks in advance!arrow_forwardA small artisanal cheesemaker is testing the acidity of their milk before it coagulates. During fermentation, bacteria produce lactic acid (K₁ = 1.4 x 104), a weak acid that helps to curdle the milk and develop flavor. The cheesemaker has measured that the developing mixture contains lactic acid at an initial concentration of 0.025 M. Your task is to calculate the pH of this mixture and determine whether it meets the required acidity for proper cheese development. To achieve the best flavor, texture and reduce/control microbial growth, the pH range needs to be between pH 4.6 and 5.0. Assumptions: Lactic acid is a monoprotic acid H H :0:0: H-C-C H :0: O-H Figure 1: Lewis Structure for Lactic Acid For simplicity, you can use the generic formula HA to represent the acid You can assume lactic acid dissociation is in water as milk is mostly water. Temperature is 25°C 1. Write the K, expression for the dissociation of lactic acid in the space provided. Do not forget to include state symbols.…arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :0: :0 H. 0:0 :0: :6: S: :0: Select to Edit Arrows ::0 Select to Edit Arrows H :0: H :CI: Rotation Select to Edit Arrows H. < :0: :0: :0: S:arrow_forward
- 3:48 PM Fri Apr 4 K Problem 4 of 10 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Mg. :0: Select to Add Arrows :0: :Br: Mg :0: :0: Select to Add Arrows Mg. Br: :0: 0:0- Br -190 H 0:0 Select to Add Arrows Select to Add Arrows neutralizing workup H CH3arrow_forwardIarrow_forwardDraw the Markovnikov product of the hydrobromination of this alkene. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for this problem. + Explanation Check 1 X E 4 1 1 1 1 1 HBr Click and drag to start drawing a structure. 80 LE #3 @ 2 $4 0 I அ2 % 85 F * K M ? BH 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center & 6 27 FG F10 8 9 R T Y U D F G H P J K L Z X C V B N M Q W A S H option command H command optiarrow_forward
- Be sure to use wedge and dash bonds to show the stereochemistry of the products when it's important, for example to distinguish between two different major products. Predict the major products of the following reaction. Explanation Q F1 A Check F2 @ 2 # 3 + X 80 F3 W E S D $ 4 I O H. H₂ 2 R Pt % 05 LL ee F6 F5 T <6 G Click and drag to start drawing a structure. 27 & A 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Acce Y U H DII 8 9 F10 4 J K L Z X C V B N M T H option command F11 P H commandarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s). Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts. H :0: CH3 O: OH Q CH3OH2+ Draw Intermediate protonation CH3OH CH3OH nucleophilic addition H Draw Intermediate deprotonation :0: H3C CH3OH2* protonation H 0: H CH3 H.arrow_forwardPredicting the reactants or products of hemiacetal and acetal formation uentify the missing organic reactants in the following reaction: H+ X+Y OH H+ за Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. ? olo 18 Ar © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY