EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 18, Problem 38P
To determine
The amount of ice in the bucket that was placed before the copper block.
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(a) Calculate the rate of heat conduction through house walls that are 13.0 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 120 m2 and their inside surface is at 18.0ºC , while their outside surface is at 5.00ºC . (b) How many 1-kW room heaters would be needed to balance the heat transfer due to conduction?
A hot, just-minted copper coin is placed in
103 g of water to cool. The water temperature
changes by 8.22°C and the temperature of the
coin changes by 88.1°C.
What is the mnss of the coin? Disregard
any energy transfer to the water's surround-
ings and assume the specific heat of copper is
387 J/kg- C. The specific heat of water is
4186 J/kg- C.
Answer in units of g-
O1. 122871
O 2. 128.638
O 3. 129.928
4. 116.608
5. 112./99
6. 139 655
8. 111.56
110.329
HO103.949
A 50 KW electric furnace measure 1.2m x 1.0m x 0.8m. When the temperature insidethe furnace is 1520 o C, a block of aluminum with a mass of 300kg and a temperatureof 16.5 o C is placed inside. Assuming the heat loss from the furnace walls is 500Watts per m 2 , how long will it take to heat the aluminum block to the furnacetemperature? Assume that the specific heat of aluminum is 0.9 KJ/kg-K.
Chapter 18 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Prob. 9PCh. 18 - Prob. 10P
Ch. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - Prob. 15PCh. 18 - Prob. 16PCh. 18 - Prob. 17PCh. 18 - Prob. 18PCh. 18 - Prob. 19PCh. 18 - Prob. 20PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - Prob. 30PCh. 18 - Prob. 31PCh. 18 - Prob. 32PCh. 18 - Prob. 33PCh. 18 - Prob. 34PCh. 18 - Prob. 35PCh. 18 - Prob. 36PCh. 18 - Prob. 37PCh. 18 - Prob. 38PCh. 18 - Prob. 39PCh. 18 - Prob. 40PCh. 18 - Prob. 41PCh. 18 - Prob. 42PCh. 18 - Prob. 43PCh. 18 - Prob. 44PCh. 18 - Prob. 45PCh. 18 - Prob. 46PCh. 18 - Prob. 47PCh. 18 - Prob. 48PCh. 18 - Prob. 49PCh. 18 - Prob. 50PCh. 18 - Prob. 51PCh. 18 - Prob. 52PCh. 18 - Prob. 53PCh. 18 - Prob. 54PCh. 18 - Prob. 55PCh. 18 - Prob. 56PCh. 18 - Prob. 57PCh. 18 - Prob. 58PCh. 18 - Prob. 59PCh. 18 - Prob. 60PCh. 18 - Prob. 61PCh. 18 - Prob. 62PCh. 18 - Prob. 63PCh. 18 - Prob. 64PCh. 18 - Prob. 65PCh. 18 - Prob. 66PCh. 18 - Prob. 67PCh. 18 - Prob. 68PCh. 18 - Prob. 69PCh. 18 - Prob. 70PCh. 18 - Prob. 71PCh. 18 - Prob. 72PCh. 18 - Prob. 73PCh. 18 - Prob. 74PCh. 18 - Prob. 75PCh. 18 - Prob. 76PCh. 18 - Prob. 77PCh. 18 - Prob. 78PCh. 18 - Prob. 79PCh. 18 - Prob. 80PCh. 18 - Prob. 81PCh. 18 - Prob. 82PCh. 18 - Prob. 83PCh. 18 - Prob. 84PCh. 18 - Prob. 85PCh. 18 - Prob. 86PCh. 18 - Prob. 87PCh. 18 - Prob. 88PCh. 18 - Prob. 89PCh. 18 - Prob. 90PCh. 18 - Prob. 91PCh. 18 - Prob. 92PCh. 18 - Prob. 93PCh. 18 - Prob. 94PCh. 18 - Prob. 95PCh. 18 - Prob. 96PCh. 18 - Prob. 97PCh. 18 - Prob. 98P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- One easy way to reduce heating (and cooling) costs is to add extra insulation in the attic of a house. Suppose a single-story cubical house already had 15 cm of fiberglass insulation in the attic and in all the exterior surfaces. If you added an extra 8.0 cm of fiberglass to the attic, by what percentage would the heating cost of the house drop? Take the house to have dimensions 10 m by 15 m by 3.0 m. Ignore air infiltration and heat loss through windows and doors, and assume that the interior is uniformly at one temperature and the exterior is uniformly at another.arrow_forwardCompare the rate of heat conduction through a 13.0-cm-thick wall that has an area of 10.0 m2 and a thermal conductivity that of glass wool with the rate of heat conduction through a 0.750-cm-thick window that has an area of 2.00 m2, assuming the same temperature difference across each.arrow_forwardIf the gas in Exercise 23 is initially at room temperature (20C) and is heated in an isobaric (constant-pressure) process, then what will be the temperature of the gas in degrees Celsius when it has expanded to a volume of 0.700 m3?arrow_forward
- To help prevent frost damage, 4.00 kg of water at 0 is sprayed onto a fruit tree. (a) How much heat transfer occurs as the water freezes? (b) How much would the temperature of the 200-kg tree decrease if this amount of heat transferred from the tree? Take the specific heat to be 3.35k J/kg. , and assume that no phase change occurs in the tree.arrow_forwardConsider the latent heat of fusion and the latent heat of vaporization for H2O, 3.33 105 J/kg and 2.256 106 J/kg, respectively. How much heat is needed to a. melt 2.00 kg of ice and b. vaporize 2.00 kg of water? Assume the temperatures of the ice and steam are at the melting point and vaporization point, respectively. (a). UsingEq21.9, Q = mLF = (2.00 kg) (3.33l05 J/kg) = 6.66105 J (b).UsingEq21.10. Q = mLV = (2.00kg) (2.256106 J/kg) = 14.51106 Jarrow_forwardA 0.250-kg aluminum bowl holding 0.800 kg of soup at 25.0 is placed in a freezer. What is the final temperature if 388 kJ of energy is transferred from the bowl and soup, assuming the soup's thermal properties are the same as that of water?arrow_forward
- Repeat the preceding problem, assuming the water is in a glass beaker with a mass of 0.200 kg, which in tum is in a calorimeter. The beaker is initially at the same temperature as the water. Before doing the problem, should the answer be higher or lower than the preceding answer? Comparing the mass and specific heat of the beaker to those of the water, do you think the beaker will make much difference?arrow_forwardA brass rod (Y=90109N/m2), with a diameter of 0.800 cm and a length of 1.20 m when the temperature is 25 , is fixed at both ends. At what temperature is the force in it at 36,000 N?arrow_forwardA 100-g piece of copper, initially at 95.0C, is dropped into 200 g of water contained in a 280-g aluminum can; the water and can are initially at 15.0C. What is the final temperature of the system? (Specific heats of copper and aluminum are 0.092 and 0.215 cal/g C. respectively.) (a) 16C (b) 18C (c) 24C (d) 26C (e) none of those answersarrow_forward
- Most automobiles have a coolant reservoir to catch radiator fluid than may overflow when 1he engine is hot. A radiator is made of copper and is filled to its 16.0L capacity when at 10.0C. What volume of radiator fluid will overflow when the radiator and fluid reach their 95.0C operating temperature, given that the fluid’s volume coefficient of expansion is =400106/C ? Note that this coefficient is approximate, because most car radiators have operating temperatures of greater than 95.0C.arrow_forwardCompute the ratio of the rate of heat loss through asingle-pane window with area 0.15 m2 to that for a double-pane windowwith the same area. The glass of a single pane is 4.2 mm thick,and the air space between the two panes of the double-pane window is7.0 mm thick. The glass has thermal conductivity 0.80 W /m . K. The airfilms on the room and outdoor surfaces of either window have a combinedthermal resistance of 0.15 m2 . K/W.arrow_forwardCalculating Heat Transfer through ConductionA polystyrene foam icebox has a total area of 0.950 m2 and walls with an average thickness of 2.50 cm. The box contains ice, water, and canned beverages at 0 °C. The inside of the box is kept cold by melting ice. Howmuch ice melts in one day if the icebox is kept in the trunk of a car at 35.0 ºC ?StrategyThis question involves both heat for a phase change (melting of ice) and the transfer of heat by conduction. To find the amount of ice melted, we must find the net heat transferred. This value can be obtained by calculating the rate of heat transfer by conduction and multiplying by time.arrow_forward
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Heat Transfer: Crash Course Engineering #14; Author: CrashCourse;https://www.youtube.com/watch?v=YK7G6l_K6sA;License: Standard YouTube License, CC-BY