EBK CHEMISTRY: PRINCIPLES AND REACTIONS
EBK CHEMISTRY: PRINCIPLES AND REACTIONS
8th Edition
ISBN: 9780100547964
Author: Hurley
Publisher: YUZU
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Chapter 18, Problem 37QAP
Interpretation Introduction

Interpretation:

The century in which the boat was built should be determined.

Concept introduction:

Activity is defined as the product of rate constant and number of atoms. It is also defined as the rate of decay or expresses number of atoms decays in unit time.

The mathematical expression is given by:

A = kN

Where, A = activity, k = first order rate constant and N = number of radioactive nuclei.

Activity can be expressed in following units:

1 Bq = 1 atom/s

1 Ci = 3.700 × 1010 atoms/s

The relation between half-life and first order rate constant is given by:

k=0.693t1/2

Where, k = first order rate constant and t1/2 = half-life

The prediction of the age of organic material is based on the rate of decay of carbon-14. Carbon-14 is an isotope of carbon which is released in the atmosphere in the form of interaction of neutrons from cosmic radiation with ordinary nitrogen atoms.

The intake of radioactive carbon stops when plant or animal dies. The reaction is given as:

614C714N+10e

The half-life of radioactive decay of carbon-14 is 5730 years. The activity of sample is directly proportional to the amount of C-14. The mathematical expression is given by:

lnAoA=kt

Where, Ao = original activity

A = measured activity

t= age of the sample

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There are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below:  QUESTION: Summarise and report these results including an indication of measurement uncertainty.  In both calculation samples calculate if an outlier is present, max value, number of samples, mean, standard deviation, g (suspect), g (critical) and t (critical).   Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32…
Indicate the rate expressions for reactions that have order 0, 1, and 2.

Chapter 18 Solutions

EBK CHEMISTRY: PRINCIPLES AND REACTIONS

Ch. 18 - Prob. 11QAPCh. 18 - Prob. 12QAPCh. 18 - Prob. 13QAPCh. 18 - Prob. 14QAPCh. 18 - Prob. 15QAPCh. 18 - Prob. 16QAPCh. 18 - Prob. 17QAPCh. 18 - Prob. 18QAPCh. 18 - Balance the following equations by filling in the...Ch. 18 - Prob. 20QAPCh. 18 - Prob. 21QAPCh. 18 - Prob. 22QAPCh. 18 - Prob. 23QAPCh. 18 - Prob. 24QAPCh. 18 - Prob. 25QAPCh. 18 - Prob. 26QAPCh. 18 - Prob. 27QAPCh. 18 - Prob. 28QAPCh. 18 - Prob. 29QAPCh. 18 - Prob. 30QAPCh. 18 - Prob. 31QAPCh. 18 - Prob. 32QAPCh. 18 - Prob. 33QAPCh. 18 - Prob. 34QAPCh. 18 - Prob. 35QAPCh. 18 - Prob. 36QAPCh. 18 - Prob. 37QAPCh. 18 - Prob. 38QAPCh. 18 - Prob. 39QAPCh. 18 - Prob. 40QAPCh. 18 - Prob. 41QAPCh. 18 - Prob. 42QAPCh. 18 - Prob. 43QAPCh. 18 - Prob. 44QAPCh. 18 - Prob. 45QAPCh. 18 - Prob. 46QAPCh. 18 - Prob. 47QAPCh. 18 - Prob. 48QAPCh. 18 - Prob. 49QAPCh. 18 - Prob. 50QAPCh. 18 - Prob. 51QAPCh. 18 - Prob. 52QAPCh. 18 - Prob. 53QAPCh. 18 - Prob. 54QAPCh. 18 - Prob. 55QAPCh. 18 - Prob. 56QAPCh. 18 - Prob. 57QAPCh. 18 - Prob. 58QAPCh. 18 - Prob. 59QAPCh. 18 - Prob. 60QAPCh. 18 - Prob. 61QAPCh. 18 - Prob. 62QAPCh. 18 - Prob. 63QAPCh. 18 - Prob. 64QAPCh. 18 - Prob. 65QAPCh. 18 - Prob. 66QAPCh. 18 - Prob. 67QAPCh. 18 - Prob. 68QAPCh. 18 - Prob. 69QAPCh. 18 - Prob. 70QAPCh. 18 - Prob. 71QAPCh. 18 - Prob. 72QAPCh. 18 - Fill in the following table:Ch. 18 - Prob. 74QAPCh. 18 - Prob. 75QAPCh. 18 - Prob. 76QAPCh. 18 - Prob. 77QAPCh. 18 - Prob. 78QAPCh. 18 - Prob. 79QAPCh. 18 - Carbon-14 (C-14) with a half-life of 5730 years...Ch. 18 - Prob. 81QAPCh. 18 - Prob. 82QAP
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