DATABASE SYSTEM CONCEPTS LCPO
7th Edition
ISBN: 9781265586577
Author: SILBERSCHATZ
Publisher: MCG
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Expert Solution & Answer
Chapter 18, Problem 35E
Explanation of Solution
Canonical cover:
A set of functional dependencies F is considered to be the minimal set of FDs that have the same closure as that of the original set of functional dependencies is called as canonical cover(Fc).
Given:
The below is the functional dependencies that is given
Expert Solution & Answer
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Students have asked these similar questions
1.) Consider the problem of determining whether a DFA and a regular expression are
equivalent. Express this problem as a language and show that it is decidable.
ii) Let ALLDFA = {(A)| A is a DFA and L(A) = "}. Show that ALLDFA is decidable.
iii) Let AECFG = {(G)| G is a CFG that generates &}. Show that AECFG is decidable.
iv) Let ETM {(M)| M is a TM and L(M) = 0}. Show that ETM, the complement of
Erm, is Turing-recognizable.
Let X be the set {1, 2, 3, 4, 5} and Y be the set {6, 7, 8, 9, 10). We describe the
functions f: XY and g: XY in the following tables. Answer each part
and give a reason for each negative answer.
n
f(n)
n
g(n)
1
6
1
10
2
7
2
9
3
6
3
8
4
7
4
7
5
6
5
6
Aa. Is f one-to-one?
b. Is fonto?
c. Is fa correspondence?
Ad. Is g one-to-one?
e. Is g onto?
f.
Is g a correspondence?
vi) Let B be the set of all infinite sequences over {0,1}. Show that B is uncountable
using a proof by diagonalization.
Can you find the least amount of different numbers to pick from positive numbers (integers) that are at most 100 to confirm two numbers that add up to 101 when each number can be picked at most two times?
Can you find the formula for an that satisfies the provided recursive definition? Please show all steps and justification
Chapter 18 Solutions
DATABASE SYSTEM CONCEPTS LCPO
Ch. 18 - Prob. 1PECh. 18 - Prob. 2PECh. 18 - Prob. 3PECh. 18 - Prob. 4PECh. 18 - Prob. 5PECh. 18 - Prob. 6PECh. 18 - Prob. 7PECh. 18 - Prob. 8PECh. 18 - Prob. 9PECh. 18 - Prob. 10PE
Ch. 18 - Prob. 11PECh. 18 - Prob. 12PECh. 18 - Prob. 13PECh. 18 - Prob. 14PECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36E
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